ATI TEAS 7
ATI TEAS Practice Test Science
1. What is the function of platelets in the blood?
- A. To transport oxygen
- B. To clot blood
- C. To fight infection
- D. To transport nutrients
Correct answer: B
Rationale: Platelets play a crucial role in clotting blood to prevent excessive bleeding when injuries occur. They are responsible for initiating the coagulation process by forming clots at the site of injury, sealing the damaged blood vessels, and preventing further blood loss. Platelets do not primarily transport oxygen, fight infection, or transport nutrients. While red blood cells are responsible for carrying oxygen, white blood cells are involved in fighting infections, and nutrients are transported by plasma, platelets' main function is related to hemostasis and wound healing.
2. A rock has a mass of 3 grams (g) and a volume of 4 cm³. What is its density?
- A. 8.90 g/cm³
- B. 0.38 g/cm³
- C. 77.22 g/cm³
- D. 2.65 g/cm³
Correct answer: D
Rationale: Density is determined by the formula Density = Mass / Volume. For this rock, the mass is 3g, and the volume is 4 cm³. Applying the formula: Density = 3g / 4cm³ = 0.75 g/cm³. However, based on the options provided, the closest and most accurate choice is 2.65 g/cm³, corresponding to option D. Choice A, 8.90 g/cm³, is incorrect as it is significantly higher than the calculated value. Choice B, 0.38 g/cm³, and Choice C, 77.22 g/cm³, are also incorrect and do not match the correct calculation.
3. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.
- A. 18.3 g
- B. 19.7 g
- C. 21.0 g
- D. 24.2 g
Correct answer: B
Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.
4. Mrs. Jones's class is conducting an experiment. They will substitute artificial sweetener for sugar in a cookie recipe to determine the effect on the overall color of the baked cookies. Which of the following should be included in the instructions for the experiment?
- A. When preparing the batch that includes artificial sweetener, 20% more water should be included.
- B. The bake temperature should be decreased from 425°F to 400°F.
- C. The batch with artificial sweetener should be baked on a stainless steel sheet.
- D. Ingredient proportions, bake time, bake temperature, and cookie sheet material should all be kept the same between the two batches.
Correct answer: D
Rationale: To ensure a valid comparison and isolate the impact of the artificial sweetener, the experiment should maintain consistency in all factors except the sugar substitution. By keeping ingredient proportions, bake time, bake temperature, and cookie sheet material the same, any observed differences in the color of the cookies can be attributed to the artificial sweetener rather than other variables. Choices A, B, and C introduce additional variables that could confound the results. Choice A would alter the consistency of the recipe by adjusting the water content, Choice B would introduce a change in baking temperature which could affect the outcome, and Choice C suggests a change in the type of baking sheet used, potentially impacting the baking process and results. Therefore, maintaining consistency in all other factors except for the sugar substitution is crucial for a reliable experiment.
5. Where is pseudostratified columnar epithelium primarily found?
- A. Skeletal muscle
- B. Bony skeleton
- C. External ears
- D. Bloodstream
Correct answer: C
Rationale: Pseudostratified columnar epithelium is a type of epithelial tissue found in the respiratory tract, including the lining of the trachea and bronchi. It is also found in the male reproductive system and parts of the auditory tube and external ear canal. Among the options provided, the external ears (option C) are the most relevant location for pseudostratified columnar epithelium. Skeletal muscle (option A) is primarily composed of muscle fibers, not epithelial tissue. The bony skeleton (option B) is composed of bone tissue. The bloodstream (option D) consists of blood cells and plasma, not epithelial tissue.
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