what is the first step in the conversion of glucose to pyruvate
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HESI A2

HESI A2 Practice Test Biology

1. What is the first step in the conversion of glucose to pyruvate?

Correct answer: A

Rationale: The correct answer is Glycolysis. Glycolysis is the initial step in the conversion of glucose to pyruvate. During glycolysis, glucose is broken down into pyruvate through a series of enzymatic reactions. Choice B, the Krebs cycle, occurs after glycolysis in aerobic cellular respiration. Choice C, the Electron transport chain, is the final step in aerobic respiration where the majority of ATP is produced. Choice D, Aerobic respiration, is a broader term that encompasses glycolysis, the Krebs cycle, and the electron transport chain, but it is not the specific first step in the conversion of glucose to pyruvate.

2. In an example of a male with hemophilia and a female carrier, what percentage of the offspring is predicted to be carriers only?

Correct answer: C

Rationale: In this scenario, the male offspring will inherit the X chromosome with the hemophilia gene from the mother, as males have one X chromosome inherited from their mother. The female offspring will inherit one normal X chromosome from the father and one X chromosome with the hemophilia gene from the mother, making them carriers of the hemophilia trait. Therefore, 50% of the offspring will be carriers only. Option A (0%) is incorrect as female offspring will inherit the X chromosome with the hemophilia gene from the mother. Option B (25%) is incorrect as the female offspring will not be unaffected. Option D (100%) is incorrect as not all offspring will be carriers, only the female offspring.

3. When the genotype consists of a dominant and a recessive allele, the phenotype will be like the _ allele.

Correct answer: A

Rationale: When the genotype consists of a dominant and a recessive allele, the phenotype will be like the dominant allele. This is because dominant alleles typically mask the expression of recessive alleles. Therefore, the dominant allele will be expressed in the phenotype in most basic cases. The recessive allele will only be expressed phenotypically if the individual is homozygous recessive. Choice B, 'Recessive,' is incorrect because the phenotype will not be like the recessive allele in this case. Choice C, 'Both,' is incorrect because in simple dominant-recessive inheritance, the dominant allele will overshadow the recessive allele. Choice D, 'Neither,' is incorrect as the phenotype will resemble the dominant allele.

4. Which of the following is true of Glycolysis?

Correct answer: B

Rationale: Glycolysis is the first step in cellular respiration and can occur in both aerobic (presence of oxygen) and anaerobic (absence of oxygen) conditions. In aerobic respiration, glycolysis takes place in the presence of oxygen and continues with the Krebs cycle and the electron transport chain. So, glycolysis does not require the absence of oxygen but can occur in its presence as part of the overall process of aerobic respiration. Choice A is incorrect because glycolysis can occur in the presence of oxygen. Choice C is incorrect because glycolysis is not the final step of fermentation; it is the initial step. Choice D is incorrect because glycolysis is not the final step of anaerobic respiration; it is the first step, followed by further processes to complete anaerobic respiration.

5. Which of these is not an example of a lipid?

Correct answer: D

Rationale: Honey is not an example of a lipid because lipids are fat-related molecules that are insoluble in water, while honey is a natural sweet substance made by bees and primarily consists of sugars such as glucose and fructose. Butter, wax, and canola oil are examples of lipids as they are all composed of fat-related molecules that do not dissolve in water.

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