Nursing Elites

1. What effect does doubling the net force applied to an object have on its acceleration, assuming mass remains constant?

• A. Acceleration doubles
• B. Acceleration is halved
• C. Acceleration remains the same
• D. Acceleration quadruples

Correct answer: A

Rationale: According to Newton's second law of motion, acceleration is directly proportional to the net force applied to an object when mass is constant. Therefore, if the net force is doubled, the acceleration of the object will also double. This relationship is expressed by the formula F=ma, where F is the net force, m is the mass, and a is the acceleration. When mass is constant, doubling the force applied will result in a proportional doubling of acceleration. Choices B, C, and D are incorrect because doubling the net force does not halve, maintain, or quadruple the acceleration; it directly and proportionally increases the acceleration.

2. When unpolarized light passes through a polarizing filter, the intensity of the transmitted light is:

• A. Completely absorbed
• B. Reduced by half
• C. Unaffected
• D. Doubled

Correct answer: B

Rationale: When unpolarized light passes through a polarizing filter, the filter only allows light waves oscillating in a specific direction to pass through while blocking light waves oscillating in other directions. Since unpolarized light consists of light waves oscillating in all possible directions, when it passes through a polarizing filter, only half of the light waves (those oscillating in the direction allowed by the filter) are transmitted. As a result, the intensity of the transmitted light is reduced by half. Choice A is incorrect because the light is not completely absorbed; choice C is incorrect because the polarizing filter affects the transmitted light; and choice D is incorrect because the intensity does not double, but rather decreases by half due to the selective transmission of light waves in a specific direction by the polarizing filter.

3. In experimental design, which variable is measured as a possible effect and is plotted on the y-axis?

• A. Independent, x
• B. Independent, y
• C. Dependent, x
• D. Dependent, y

Correct answer: D

Rationale: The correct answer is D: 'Dependent, y.' In experimental design, the dependent variable is the outcome that is being measured or observed as a result of changes in the independent variable. It is typically plotted on the y-axis of a graph to represent the effect or response to the changes in the independent variable. Choice A 'Independent, x' is incorrect because the independent variable is the variable manipulated by the experimenter and is usually plotted on the x-axis. Choice B 'Independent, y' is incorrect as the independent variable is not plotted on the y-axis. Choice C 'Dependent, x' is incorrect because the dependent variable is not typically plotted on the x-axis in experimental design.

4. Which type of blood vessel carries blood away from the heart?

• A. Vein
• B. Artery
• C. Capillary
• D. Venule

Correct answer: B

Rationale: The correct answer is B: Artery. Arteries carry oxygen-rich blood away from the heart to various parts of the body. Veins, on the other hand, carry blood back to the heart. Capillaries are tiny blood vessels where oxygen and nutrients are exchanged with tissues. Venules are small veins that collect blood from capillaries, not from the heart, making them incorrect in this context.

5. How do hydrogen bonds in water affect its characteristics?

• A. Hydrogen bonds are not polar enough to attract non-polar molecules.
• B. Hydrogen bonds cause water to be less dense when it is a solid than when it is a liquid.
• C. Hydrogen bonds cause water to have high surface tension, allowing some organisms to move across it.
• D. Hydrogen bonds cause water to be a good solvent.

Correct answer: C

Rationale: Hydrogen bonds in water contribute to its high surface tension, enabling some organisms to move across the water's surface. This property is essential for certain insects and small animals that rely on surface tension to move or stay afloat on water. Choice A is incorrect because hydrogen bonds are polar and can attract polar and other charged molecules. Choice B is incorrect as hydrogen bonds make ice less dense than liquid water, which is a unique property. Choice D is incorrect as the ability of water to act as a good solvent is primarily due to its polarity, not just hydrogen bonding.

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