ATI TEAS 7
TEAS Math Questions
1. University Q has an extremely competitive nursing program. Historically, 3/4 of the students in each incoming class major in nursing, but only 1/3 of those who major in nursing actually complete the program. If this year’s incoming class has 100 students, how many students will complete the nursing program?
- A. 75
- B. 20
- C. 25
- D. 5
Correct answer: C
Rationale: Out of 100 students, 3/4 major in nursing, which is 75 students (100 * 3/4 = 75). Among these 75 students, only 1/3 will complete the program. Therefore, 1/3 of 75 is 25. Hence, 25 students will complete the nursing program. Choice A (75) is incorrect because this represents the number of students majoring in nursing, not completing the program. Choices B (20) and D (5) are incorrect as they do not align with the calculation based on the given fractions and total number of students.
2. Veronica is making a holiday schedule. 35% of staff members will be on vacation, and 20% of the remainder are certified to work. What percentage of the staff is certified and available?
- A. 0.07
- B. 0.13
- C. 0.65
- D. 0.8
Correct answer: A
Rationale: To find the percentage of staff certified and available, we first calculate the percentage of staff members not on vacation, which is 100% - 35% = 65%. Then, 20% of this group is certified to work, which is 20% of 65% = 0.20 * 65% = 13%. Therefore, Veronica has 13% of the staff certified and available to work. The correct answer is 0.13 (or 13%). Choice C (0.65) is incorrect because it represents the percentage of staff members not on vacation, not the percentage that is certified and available. Choice D (0.8) is incorrect as it is not the correct percentage of staff members certified and available. Choice B (0.13) is the correct answer, not choice A (0.07), as 0.07 represents 7%, not 13%.
3. Which of the following statements is true?
- A. The mean is less than the median
- B. The mode is greater than the median
- C. The mode is less than the mean, median, and range
- D. The mode is equal to the range
Correct answer: A
Rationale: The mean is the average of a set of numbers, while the median is the middle value when the numbers are arranged in order. If a set of numbers is skewed to one side with some outliers, the mean can be influenced by these extreme values, causing it to be greater or less than the median. In cases of skewed distribution, the mean typically shifts towards the direction of the outliers, making it less than the median. Choice B is incorrect because the mode, which is the most frequent number in a dataset, may or may not be greater than the median. Choice C is incorrect because the mode can be greater than the mean or median, depending on the data. Choice D is incorrect because the mode, representing the most frequent value, has no direct relationship with the range, which is the difference between the highest and lowest values in a dataset.
4. What is the value of b in this equation? 5b - 4 = 2b + 17
- A. 13
- B. 24
- C. 7
- D. 21
Correct answer: C
Rationale: To find the value of b in the equation 5b - 4 = 2b + 17, you need to first simplify the equation. By subtracting 2b from both sides of the equation and adding 4 to both sides, you get 3b = 21. Then, dividing both sides of the equation by 3 gives you b = 7. Therefore, the value of b is 7, which corresponds to option C. Choice A (13) is incorrect as it does not match the correct calculation. Choice B (24) is incorrect as it is not the result of the correct algebraic manipulation. Choice D (21) is incorrect as it is not the value of b obtained after solving the equation step by step.
5. A patient was taking 310 mg of an antidepressant daily. The doctor reduced the dosage by 1/5, and then reduced it again by 20 mg. What is the patient’s final dosage?
- A. 20 mg
- B. 42 mg
- C. 228 mg
- D. 248 mg
Correct answer: C
Rationale: To calculate the final dosage, first find 1/5 of 310 mg, which is 62 mg, and subtract it from the original dosage. This gives 310 mg - 62 mg = 248 mg. Then, subtract an additional 20 mg from the result to get the final dosage: 248 mg - 20 mg = 228 mg. Therefore, the patient's final dosage is 228 mg. Choice A (20 mg) is incorrect because it only considers the second reduction of 20 mg and misses the initial reduction by 1/5. Choice B (42 mg) is incorrect as it miscalculates the reduction amounts. Choice D (248 mg) is incorrect as it does not account for the second reduction of 20 mg.
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