ATI TEAS 7
TEAS Math Questions
1. A set of patients is divided into groups: 1/2 in Group Alpha, 1/3 in Group Beta, and 1/6 in Group Gamma. Order the groups from smallest to largest.
- A. Alpha, Beta, Gamma
- B. Alpha, Gamma, Beta
- C. Gamma, Alpha, Beta
- D. Gamma, Beta, Alpha
Correct answer: C
Rationale: To determine the order from smallest to largest groups, we look at the fractions representing the groups. Group Gamma has 1/6, which is the smallest fraction, followed by Group Alpha with 1/2, and Group Beta with 1/3 being the largest fraction. So, the correct order is Gamma, Alpha, Beta. Choice A is incorrect because it lists Alpha, Beta, Gamma, which is the reverse order. Choice B is incorrect as it lists Alpha, Gamma, Beta, which is also incorrect. Choice D is incorrect as it lists Gamma, Beta, Alpha, which is not the correct order based on the fractions provided.
2. What is a prime number?
- A. A number divisible by only 1 and itself
- B. A number divisible by 2 and 3
- C. A number divisible by any number
- D. A number with exactly three factors
Correct answer: A
Rationale: The correct answer is A: 'A number divisible by only 1 and itself.' A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers. This definition aligns with choice A. Choice B is incorrect because not all prime numbers are divisible by 2 and 3. Choice C is incorrect as prime numbers are not divisible by any number other than 1 and themselves. Choice D is incorrect because a prime number has exactly two factors, 1 and itself, not three factors.
3. If 9.5% of a town's population of 51,623 people voted for a proposition, approximately how many people voted for the proposition?
- A. 3000
- B. 5000
- C. 7000
- D. 10000
Correct answer: B
Rationale: To find the approximate number of people who voted for the proposition, multiply the town's population by the percentage that voted: 51,623 * 9.5% = 51,623 * 0.095 ≈ 4,904. Therefore, approximately 5,000 people voted for the proposition. Choice A (3000), C (7000), and D (10000) are incorrect because they do not accurately represent 9.5% of the town's population.
4. Which of the following statements is true?
- A. The mean is less than the median
- B. The mode is greater than the median
- C. The mode is less than the mean, median, and range
- D. The mode is equal to the range
Correct answer: A
Rationale: The mean is the average of a set of numbers, while the median is the middle value when the numbers are arranged in order. If a set of numbers is skewed to one side with some outliers, the mean can be influenced by these extreme values, causing it to be greater or less than the median. In cases of skewed distribution, the mean typically shifts towards the direction of the outliers, making it less than the median. Choice B is incorrect because the mode, which is the most frequent number in a dataset, may or may not be greater than the median. Choice C is incorrect because the mode can be greater than the mean or median, depending on the data. Choice D is incorrect because the mode, representing the most frequent value, has no direct relationship with the range, which is the difference between the highest and lowest values in a dataset.
5. Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?
- A. $1.75
- B. $2.00
- C. $2.25
- D. $2.50
Correct answer: C
Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25. Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.
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