ATI TEAS 7
TEAS 7 Math Practice Test
1. Tom needs to buy ink cartridges and printer paper. Each ink cartridge costs $30. Each ream of paper costs $5. He has $100 to spend. Which of the following inequalities may be used to find the combinations of ink cartridges and printer paper he may purchase?
- A. 30c + 5p ≤ 100
- B. 30c + 5p = 100
- C. 30c + 5p > 100
- D. 30c + 5p < 100
Correct answer: A
Rationale: The correct inequality is 30c + 5p ≤ 100. This represents the combinations of ink cartridges (c) and printer paper (p) that Tom may purchase, ensuring the total cost is less than or equal to $100. Choice B is incorrect because the total cost should be less than or equal to $100, not equal to. Choices C and D are also incorrect as they indicate the total cost being greater than $100, which is not the case given Tom's budget limit.
2. Complete the following equation: x + x * x - x / x = ?
- A. 5
- B. 3
- C. 2
- D. 1
Correct answer: B
Rationale: To solve the equation x + x * x - x / x, follow the order of operations (PEMDAS/BODMAS). First, perform the multiplication: x * x = x^2. Then, perform the division: x / x = 1. Substituting these back into the equation gives x + x^2 - 1. Therefore, the equation simplifies to x + x^2 - 1. By evaluating this further, the final result is 3. Choices A, C, and D are incorrect because they do not correctly apply the order of operations to solve the equation.
3. A farmer plans to install fencing around a certain field. If each side of the hexagonal field is 320 feet long, and fencing costs $75 per foot, how much will the farmer need to spend on fencing material to enclose the perimeter of the field?
- A. $2,240
- B. $2,800
- C. $3,360
- D. $4,480
Correct answer: C
Rationale: The field is a hexagon with six equal sides, each 320 feet long. To find the total cost of fencing material needed, multiply the cost per foot ($75) by the total perimeter of the field (6 sides x 320 feet). Therefore, the total cost will be $75 x 6 x 320 = $3,360. Thus, the farmer will need to spend $3,360 on fencing material. Choice A, $2,240, is incorrect as it does not account for the total perimeter of the field. Choice B, $2,800, is incorrect as it underestimates the total cost by not considering all sides of the hexagon. Choice D, $4,480, is incorrect as it overestimates the total cost by multiplying incorrectly or considering extra sides.
4. How many whole boxes measuring 2 ft * 2 ft * 2 ft can be stored in a room measuring 9 ft * 9 ft * 9 ft, without altering the box size?
- A. 125
- B. 64
- C. 18
- D. 92
Correct answer: D
Rationale: The total volume of the room is 729 ft³ (9 ft * 9 ft * 9 ft). Each box has a volume of 8 ft³ (2 ft * 2 ft * 2 ft). Dividing the room's volume by the box volume, we get 729 ft³ / 8 ft³ ≈ 91.125. Since we can't have a fraction of a box, the maximum number of whole boxes that can fit is 92. Therefore, the correct answer is 92. Choice A (125) is incorrect as it does not result from the correct calculation. Choice B (64) and Choice C (18) are also incorrect and do not accurately represent the number of boxes that can fit in the room based on the given dimensions.
5. What is the average length of a human eyelash?
- A. 1 nanometer
- B. 1 centimeter
- C. 1 meter
- D. 1 kilometer
Correct answer: B
Rationale: The average length of a human eyelash is approximately one centimeter. A nanometer is too small to describe the length of an eyelash. A meter and a kilometer are much longer lengths and not suitable to describe the average human eyelash.
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