ATI TEAS 7
TEAS Practice Math Test
1. Jerry needs to load four pieces of equipment onto a factory elevator that has a weight limit of 800 pounds. Jerry weighs 200 pounds. What would be the average weight of each item so that the elevator's weight limit is not exceeded?
- A. 128 pounds
- B. 150 pounds
- C. 175 pounds
- D. 180 pounds
Correct answer: B
Rationale: To find the average weight per item, subtract Jerry's weight from the elevator's weight limit: 800 - 200 = 600 pounds. Since there are 4 items, divide 600 by 4 to determine that each item should weigh 150 pounds. Choice A (128 pounds), C (175 pounds), and D (180 pounds) are incorrect as they do not correctly calculate the average weight per item to ensure the elevator's weight limit is not exceeded.
2. A study was conducted where patients were divided into three groups: 1/2 in Group Alpha, 1/3 in Group Beta, and 1/6 in Group Gamma. Which group is the smallest?
- A. Group Alpha
- B. Group Beta
- C. Group Gamma
- D. Group Gamma
Correct answer: C
Rationale: The smallest group is Group Gamma, which had 1/6 of the total number of patients. To determine the smallest group, compare the fractions representing the portions of patients in each group. 1/6 is smaller than 1/3 and 1/2, making Group Gamma the smallest. Group Alpha and Group Beta have larger fractions of patients, making them larger groups compared to Group Gamma.
3. Which of the following describes a proportional relationship?
- A. Johnathan opens a savings account with an initial deposit of $150 and deposits $125 per month
- B. Bruce pays his employees $12 per hour worked during the month of December, as well as a $250 bonus
- C. Alvin pays $28 per month for his phone service plus $0.07 for each long-distance minute used
- D. Kevin drives 65 miles per hour
Correct answer: A
Rationale: A proportional relationship is one in which two quantities vary directly with each other. In choice A, the amount deposited per month is directly proportional to the initial deposit. The relationship can be represented as y = 125x + 150, where x is the number of months and y is the total amount in the account. Choices B and C involve additional fixed amounts or variable costs that do not maintain a constant ratio, making them non-proportional relationships. Choice D refers to a constant speed of driving, which is not a proportional relationship as it does not involve varying quantities that change in direct proportion.
4. University X requires some of its nursing students to take an exam before being admitted into the nursing program. In this year's class, half of the nursing students were required to take the exam, and three-fifths of those who took the exam passed. If this year's class has 200 students, how many students passed the exam?
- A. 120
- B. 100
- C. 60
- D. 50
Correct answer: C
Rationale: If the incoming class has 200 students, then half of those students were required to take the exam. (200)(1/2) = 100. So 100 students took the exam, but only three-fifths of that 100 passed the exam. (100)(3/5) = 60. Therefore, 60 students passed the exam. The correct answer is 60. Choice A is incorrect as it miscalculates the number of students who passed the exam. Choice B is incorrect as it does not consider the passing rate of the exam. Choice D is incorrect as it is much lower than the correct answer.
5. What is the sum of two odd numbers, two even numbers, and an odd number and an even number?
- A. Odd + Odd = Even; Even + Even = Even; Odd + Even = Odd
- B. Odd + Odd = Odd; Even + Even = Even; Odd + Even = Even
- C. Odd + Odd = Even; Even + Even = Odd; Odd + Even = Even
- D. Odd + Odd = Odd; Even + Even = Odd; Odd + Even = Even
Correct answer: A
Rationale: The sum of two odd numbers is even because odd numbers have a difference of 1 and adding them results in a multiple of 2. The sum of two even numbers is even because even numbers are multiples of 2. When an odd number and an even number are added, the result is odd because the even number contributes an extra 1 to the sum, making it an odd number. Therefore, the correct answer is A. Choices B, C, and D have incorrect combinations of the sum of odd and even numbers.
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