Nursing Elites

1. Jerry needs to load four pieces of equipment onto a factory elevator that has a weight limit of 800 pounds. Jerry weighs 200 pounds. What would be the average weight of each item so that the elevator's weight limit is not exceeded?

• A. 128 pounds
• B. 150 pounds
• C. 175 pounds
• D. 180 pounds

Correct answer: B

Rationale: To find the average weight per item, subtract Jerry's weight from the elevator's weight limit: 800 - 200 = 600 pounds. Since there are 4 items, divide 600 by 4 to determine that each item should weigh 150 pounds. Choice A (128 pounds), C (175 pounds), and D (180 pounds) are incorrect as they do not correctly calculate the average weight per item to ensure the elevator's weight limit is not exceeded.

2. What is the probability of flipping a coin and getting heads?

• A. 1/2
• B. 1/3
• C. 1/4
• D. 1/5

Correct answer: A

Rationale: The correct answer is A: 1/2. When flipping a fair coin, there are two possible outcomes: heads or tails. The probability of getting heads is 1 out of 2 possible outcomes, which can be expressed as 1/2. Choice B, 1/3, is incorrect because a fair coin only has two sides. Choices C and D, 1/4 and 1/5, are also incorrect as they do not represent the correct probability of getting heads when flipping a coin.

3. How many kilometers is 4382 feet?

• A. 1.336 kilometers
• B. 14.376 kilometers
• C. 1.437 kilometers
• D. 13.336 kilometers

Correct answer: A

Rationale: To convert feet to kilometers, you need to divide the number of feet by 3280.84 (the number of feet in a kilometer). Therefore, 4382 feet is equal to 4382/3280.84 ≈ 1.336 kilometers. Choice B, 14.376 kilometers, is incorrect as it seems to be a miscalculation. Choice C, 1.437 kilometers, is also incorrect, as it is slightly off from the correct conversion. Choice D, 13.336 kilometers, is significantly higher than the correct answer and does not align with the conversion factor.

4. If , then

• A. 1
• B. 2
• C. 3
• D. 4

Correct answer: C

Rationale: If \(2x = 6\), then solving for \(x\), we have \(x = \frac{6}{2} = 3\). So, if \(x = 3\), then \(x+1 = 3+1 = 4\). Therefore, the value of \(x+1\) would be 4.

5. A commuter survey counts the people riding in cars on a highway in the morning. Each car contains only one man, only one woman, or both one man and one woman. Out of 25 cars, 13 contain a woman and 20 contain a man. How many contain both a man and a woman?

• A. 4
• B. 7
• C. 8
• D. 13

Correct answer: C

Rationale: Let's denote the number of cars containing only a man as M, only a woman as W, and both a man and a woman as B. Given that there are 25 cars in total, we have: M + W + B = 25 From the information provided, we know that 13 cars contain a woman (W) and 20 cars contain a man (M). Since each car contains either one man, one woman, or both, the cars that contain both a man and a woman (B) are counted once in each of the M and W categories. Therefore, to find out how many cars contain both a man and a woman, we need to subtract the number of cars that contain only a man and only a woman from the total cars. M + B = 20 (as 20 cars contain a man) W + B = 13 (as 13 cars contain a woman) Solving the above two equations simultaneously, we get: M = 12, W = 5, B = 8 Therefore, 8 cars contain both a man and a woman. Hence, the correct answer is 8. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on the information provided.

Similar Questions