Nursing Elites

1. What is the sum of two odd numbers, two even numbers, and an odd number and an even number?

• A. Odd + Odd = Even; Even + Even = Even; Odd + Even = Odd
• B. Odd + Odd = Odd; Even + Even = Even; Odd + Even = Even
• C. Odd + Odd = Even; Even + Even = Odd; Odd + Even = Even
• D. Odd + Odd = Odd; Even + Even = Odd; Odd + Even = Even

Correct answer: A

Rationale: The sum of two odd numbers is even because odd numbers have a difference of 1 and adding them results in a multiple of 2. The sum of two even numbers is even because even numbers are multiples of 2. When an odd number and an even number are added, the result is odd because the even number contributes an extra 1 to the sum, making it an odd number. Therefore, the correct answer is A. Choices B, C, and D have incorrect combinations of the sum of odd and even numbers.

2. A woman wants to stack two bookcases, one 32.75 inches tall and another 17.25 inches tall. How tall will they be when stacked together?

• A. 49.5 inches
• B. 50 inches
• C. 48 inches
• D. 51 inches

Correct answer: B

Rationale: To find the total height of the stacked bookcases, you need to add the heights of the two bookcases: 32.75 inches + 17.25 inches = 50 inches. Therefore, the correct answer is 50 inches. Choice A (49.5 inches) is incorrect as it does not consider rounding off the total height. Choices C (48 inches) and D (51 inches) are incorrect as they do not accurately calculate the sum of the heights of the two bookcases.

3. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

4. What is a common denominator?

• A. A shared multiple of two denominators
• B. A shared factor of two numerators
• C. A number that is the same in all fractions
• D. A number that divides evenly into both fractions

Correct answer: A

Rationale: A common denominator is a shared multiple of the denominators in a set of fractions. It is necessary when adding or subtracting fractions to have a common denominator to ensure that the fractions can be combined accurately. Choice B is incorrect because the common denominator is related to the denominators, not the numerators. Choice C is incorrect because while the common denominator is the same in all fractions being added or subtracted, it is not necessarily a number that is the same in all fractions. Choice D is incorrect because a common denominator is a multiple of the denominators, not a number that divides evenly into both fractions.

5. University X requires some of its nursing students to take an exam before being admitted into the nursing program. In this year's class, half of the nursing students were required to take the exam, and three-fifths of those who took the exam passed. If this year's class has 200 students, how many students passed the exam?

• A. 120
• B. 100
• C. 60
• D. 50

Correct answer: C

Rationale: If the incoming class has 200 students, then half of those students were required to take the exam. (200)(1/2) = 100. So 100 students took the exam, but only three-fifths of that 100 passed the exam. (100)(3/5) = 60. Therefore, 60 students passed the exam. The correct answer is 60. Choice A is incorrect as it miscalculates the number of students who passed the exam. Choice B is incorrect as it does not consider the passing rate of the exam. Choice D is incorrect as it is much lower than the correct answer.

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