ATI TEAS 7
TEAS Test Practice Math
1. Solve the following equation: 3(2y+50)−4y=500
- A. y = 125
- B. y = 175
- C. y = 150
- D. y = 200
Correct answer: B
Rationale: To solve the equation 3(2y+50)−4y=500, first distribute to get 6y+150−4y=500. Combining like terms results in 2𝑦 + 150 = 500. By subtracting 150 from both sides, we get 2y = 350. Dividing by 2 gives y = 175. Therefore, the correct answer is B. Choices A, C, and D are incorrect because they do not correctly follow the steps of distributing, combining like terms, and isolating the variable to solve for y.
2. In Mrs. McConnell's classroom, there are 5 students with hazel eyes and 2 students with green eyes out of a total of 30 students. What percentage of the students have either hazel or green eyes?
- A. 0.23
- B. 0.3
- C. 0.47
- D. 0.77
Correct answer: A
Rationale: To calculate the percentage of students with either hazel or green eyes, add the number of students with hazel and green eyes (5 + 2 = 7) and divide by the total number of students (30): 7 ÷ 30 ≈ 0.23 or 23%. The correct answer is A, 0.23, which represents 23% of the total students. Choice B, 0.3, is incorrect as it corresponds to 30%, which is higher than the total number of students. Choice C, 0.47, is incorrect as it represents 47%, which is also higher than the total number of students. Choice D, 0.77, is incorrect as it corresponds to 77%, which is much higher than the total number of students.
3. Express 3 5/7 as an improper fraction.
- A. 26/7
- B. 21/7
- C. 22/7
- D. 26/5
Correct answer: A
Rationale: To convert a mixed number to an improper fraction, multiply the whole number by the denominator of the fraction, then add the numerator. In this case, 3 * 7 + 5 = 21 + 5 = 26. So, 3 5/7 as an improper fraction is 26/7. Choice B (21/7) is incorrect because it represents the original fraction 3 5/7. Choice C (22/7) is incorrect and represents a different fraction. Choice D (26/5) is incorrect and does not reflect the proper conversion of the mixed number to an improper fraction.
4. In the winter of 2006, 6 inches of snow fell in Chicago, IL. The following winter, 3 inches of snowfall fell in Chicago. What was the percent decrease in snowfall in Chicago between those two winters?
- A. 69.40%
- B. 59.00%
- C. 41.00%
- D. 24.70%
Correct answer: C
Rationale: To calculate the percent decrease in snowfall between the two winters, use the formula: Percent Decrease = ((Initial Value - Final Value) / Initial Value) * 100. In this case, the initial value is 6 inches and the final value is 3 inches. Plug these values into the formula: ((6 - 3) / 6) * 100 = (3 / 6) * 100 = 0.5 * 100 = 50%. Therefore, the correct answer is 50%, which is not listed among the choices provided. Among the given choices, the closest percentage is 41.00%, which corresponds to choice C.
5. Three roommates decided to combine their money to buy a birthday gift for the fourth roommate. The first roommate contributed $12.03, the second roommate gave $11.96, and the third roommate donated $12.06. Estimate the total amount of money the roommates used to purchase the gift
- A. $34
- B. $35
- C. $36
- D. $37
Correct answer: C
Rationale: To find the total amount contributed, you can add the individual contributions: $12.03 + $11.96 + $12.06 = $36. Therefore, the roommates used a total of $36 to purchase the gift. Choice A ($34), B ($35), and D ($37) are incorrect as they do not reflect the accurate total amount contributed by the roommates.
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