Nursing Elites

1. Solve for x in the equation above: (x/y) - z = rw

• A. X = y(z + rw)
• B. X = rw(y - z)
• C. X = rwy + z
• D. X = rwy - z

Correct answer: A

Rationale: To solve for x, first, isolate x by moving the term involving x to one side of the equation. Begin by adding z to both sides of the equation to get (x/y) = rw + z. Then, multiply both sides by y to get x = y(rw + z), which simplifies to x = y(z + rw). Therefore, choice A is correct. Choices B, C, and D are incorrect because they do not correctly rearrange the terms in the equation to solve for x.

2. Simplify the following expression: 7 + 16 - (5 + 6 × 3) - 10 × 2

• A. -42
• B. -20
• C. 23
• D. 20

Correct answer: B

Rationale: Start by solving the multiplication and parentheses. The answer is -20.

3. How many cubic inches of water could the aquarium hold if it were filled completely? (Dimensions: 30 in × 10 in × 12 in)

• A. 3600 cubic inches
• B. 52 cubic inches
• C. 312 cubic inches
• D. 1144 cubic inches

Correct answer: A

Rationale: To find the volume of the aquarium, we multiply its length, width, and height. The formula for the volume of a rectangular solid is V = l × w × h. Substituting the given dimensions, we get V = 30 × 10 × 12 = 3600 cubic inches. Therefore, the aquarium can hold 3600 cubic inches of water. Choice B (52 cubic inches), Choice C (312 cubic inches), and Choice D (1144 cubic inches) are incorrect as they do not correctly calculate the volume of the aquarium based on its dimensions.

4. What is the best estimate in meters for the average width of a doorway?

• A. 0.5
• B. 1
• C. 10
• D. 3

Correct answer: B

Rationale: The correct answer is B: 1. The average width of a doorway typically ranges from 0.8 to 1.2 meters, making 1 meter a reasonable estimate. Choice A (0.5) is too narrow for a standard doorway. Choice C (10) is too wide for a typical doorway. Choice D (3) is also wider than the standard width of a doorway.

5. As part of a study, a set of patients will be divided into three groups. 4/15 of the patients will be in Group Alpha, 2/5 in Group Beta, and 1/3 in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.

• A. Group Alpha, Group Beta, Group Gamma
• B. Group Alpha, Group Gamma, Group Beta
• C. Group Gamma, Group Alpha, Group Beta
• D. Group Alpha, Group Beta, Group Gamma

Correct answer: B

Rationale: The correct order is Group Alpha, Group Gamma, Group Beta based on the common denominators of the fractions. To determine the order from smallest to largest, compare the fractions' numerators since the denominators are different. Group Alpha has 4/15 patients, Group Gamma has 1/3 patients, and Group Beta has 2/5 patients. Comparing the fractions' numerators, the order from smallest to largest is Group Alpha (4), Group Gamma (1), and Group Beta (2). Therefore, the correct order is Group Alpha, Group Gamma, Group Beta. Choice A is incorrect as it lists Group Beta before Group Gamma. Choice C is incorrect as it lists Group Gamma before Group Alpha. Choice D is incorrect as it lists Group Beta before Group Gamma, which is not in ascending order based on the number of patients.

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