simplify the following expression 14 35 1 18
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ATI TEAS 7

ATI TEAS Math Practice Test

1. Simplify the following expression: (1/4) × (3/5) ÷ 1 (1/8)

Correct answer: C

Rationale: First, convert the mixed number 1 (1/8) into an improper fraction: 1 (1/8) = 9/8. Now, simplify the expression: (1/4) × (3/5) ÷ (9/8). To divide by a fraction, multiply by its reciprocal: (1/4) × (3/5) × (8/9) = 24/180 = 2/15. Thus, the simplified expression is 2/15. Choice A (8/15) is incorrect because the correct answer is 2/15. Choice B (27/160) is incorrect as it is not the result of the given expression. Choice D (27/40) is incorrect as it does not match the simplified expression obtained.

2. If you pull an orange block from a bag of 3 orange, 5 green, and 4 purple blocks, what is the probability of consecutively pulling two more orange blocks without replacement?

Correct answer: B

Rationale: To calculate the probability of pulling two more orange blocks consecutively without replacement after the initial orange block is pulled, we need to multiply the probabilities. After the first orange block is pulled, there are 2 orange blocks left out of a total of 11 blocks remaining. So, the probability of pulling a second orange block is 2/11. Therefore, the overall probability is (3/12) * (2/11) = 3/55. Choice A (1/12) is incorrect because it only considers the probability of the first orange block being pulled. Choice C (1/55) is incorrect as it represents the probability of pulling two orange blocks in a row, not the consecutive pulls after the initial pull. Choice D (2/33) is incorrect as it does not reflect the correct calculation for the consecutive pulls of orange blocks.

3. How many feet are in 9 yards?

Correct answer: D

Rationale: To convert yards to feet, you need to know that 1 yard is equal to 3 feet. Therefore, to find out how many feet are in 9 yards, you multiply 9 by 3, which equals 27 feet. Choice A (45 ft) is incorrect as it miscalculates by multiplying 9 by 5 instead of 3. Choice B (18 ft) incorrectly multiplies 9 by 2. Choice C (36 ft) is incorrect as it doubles the answer of 18 feet, which is also an incorrect calculation.

4. A commuter survey counts the people riding in cars on a highway in the morning. Each car contains only one man, only one woman, or both one man and one woman. Out of 25 cars, 13 contain a woman and 20 contain a man. How many contain both a man and a woman?

Correct answer: C

Rationale: Let's denote the number of cars containing only a man as M, only a woman as W, and both a man and a woman as B. Given that there are 25 cars in total, we have: M + W + B = 25 From the information provided, we know that 13 cars contain a woman (W) and 20 cars contain a man (M). Since each car contains either one man, one woman, or both, the cars that contain both a man and a woman (B) are counted once in each of the M and W categories. Therefore, to find out how many cars contain both a man and a woman, we need to subtract the number of cars that contain only a man and only a woman from the total cars. M + B = 20 (as 20 cars contain a man) W + B = 13 (as 13 cars contain a woman) Solving the above two equations simultaneously, we get: M = 12, W = 5, B = 8 Therefore, 8 cars contain both a man and a woman. Hence, the correct answer is 8. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on the information provided.

5. Which of the following is the greatest value?

Correct answer: B

Rationale: To determine the greatest value among the choices, you need to convert all options to a common format. In this case, converting fractions to decimals will help compare them. When 7 ÷ 5 is calculated, it equals 1.4, which is greater than 0.729 (choice C) and 0.78 (choice A when rounded). The percentage 73% (choice D) is equivalent to 0.73, making 7 ÷ 5 the largest value. Therefore, the correct answer is B. Choice A is smaller than B, as 43 ÷ 55 equals approximately 0.78. Choice C is smaller than B, as 0.729 is less than 1.4. Choice D is smaller than B, as 73% is equal to 0.73, which is less than 1.4.

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