Nursing Elites

1. What do Newton's rings visually demonstrate?

• A. Diffraction
• B. Doppler effect
• C. Polarization
• D. Thin-film interference

Correct answer: D

Rationale: Newton's rings are a series of concentric colored rings observed when light is reflected between a spherical surface and a flat surface. This phenomenon is a result of thin-film interference, where light waves reflecting off the two surfaces interfere with each other constructively or destructively, leading to the observed pattern of rings. Diffraction, polarization, and the Doppler effect are not related to the specific phenomenon of Newton's rings. Diffraction refers to the bending of waves around obstacles, polarization deals with the orientation of electromagnetic waves, and the Doppler effect relates to the change in frequency of waves due to motion. Therefore, the correct answer is thin-film interference, as it precisely describes the phenomenon observed in Newton's rings.

2. How does friction affect motion?

• A. Friction increases speed
• B. Friction decreases speed
• C. Friction has no impact on speed
• D. Friction causes objects to float

Correct answer: B

Rationale: Friction is a force that opposes motion when two surfaces are in contact. It acts in the opposite direction to the direction of motion, causing objects to slow down or come to a stop. Therefore, friction decreases speed rather than increasing it. Choice A is incorrect as friction does not increase speed but rather hinders it. Choice C is incorrect because friction does have an impact on speed by slowing down objects. Choice D is incorrect as friction's effect is not making objects float but rather causing resistance to motion.

3. During which phase of the cell cycle does cytokinesis typically occur?

• A. Interphase
• B. Mitosis
• C. Meiosis
• D. G2 phase

Correct answer: B

Rationale: Cytokinesis is the process of dividing the cytoplasm of a cell into two daughter cells after the nucleus has divided during mitosis. In the cell cycle, cytokinesis typically occurs at the end of the mitotic phase, following the separation of the duplicated chromosomes into two identical sets in the daughter nuclei. Interphase (option A) is the phase where the cell grows, carries out its normal functions, and prepares for cell division, but cytokinesis does not occur during this phase. Meiosis (option C) is a specialized type of cell division that occurs in sexually reproducing organisms to produce gametes, and cytokinesis occurs at the end of meiosis II, not meiosis I. G2 phase (option D) is the phase of the cell cycle following DNA replication in S phase and preceding mitosis, where the cell prepares for cell division, but cytokinesis occurs during mitosis, not in the G2 phase.

4. What is the name of the strong acid produced by the stomach to help break down food?

• A. Hydrochloric acid
• B. Lactic acid
• C. Bile
• D. Fatty acid

Correct answer: A

Rationale: The correct answer is A, hydrochloric acid. The stomach produces hydrochloric acid to aid in the digestion process by breaking down food, particularly proteins. This acid is crucial for the proper absorption of nutrients in the stomach. Lactic acid is produced in muscles during intense exercise, not in the stomach. Bile is produced by the liver to assist in digestion, primarily in the small intestine, not in the stomach. Fatty acids are molecules found in fats with different functions in the body, but they are not the primary acid produced by the stomach for digestion.

5. What is the work done by a force of 20 N acting on an object that moves 5 meters in the direction of the force?

• A. 100 Joules (J)
• B. 25 Joules (J)
• C. 4 Joules (J)
• D. Work cannot be determined without knowing the object's mass.

Correct answer: A

Rationale: The work done is calculated using the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. In this case, the force and the direction of motion are in the same direction, so cos(theta) = 1. Therefore, Work = 20 N x 5 m x 1 = 100 Joules. Since the force and distance are given and are in the same direction, the work done can be directly calculated without needing to know the object's mass. Choice A, 100 Joules, is the correct answer as calculated. Choice B and C are incorrect as they do not correspond to the correct calculation. Choice D is incorrect because knowing the object's mass is not necessary to calculate work in this scenario, as work is dependent on force, distance, and the angle between them, not mass.

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