long bones are one of the five major types of bone in the human body all of the following bones are long bones except

ATI TEAS 7

ATI TEAS Science Test

1. Long bones are one of the five major types of bones in the human body. All of the following bones are long bones, EXCEPT

A. Thighs
B. Forearms
C. Ankles
D. Fingers

Correct answer: D

Rationale: Long bones are one of the five major types of bones in the human body, characterized by their elongated shape. Thighs, forearms, and ankles are examples of long bones as they are longer than they are wide and have a tubular structure, aiding in support and movement. Fingers, however, are categorized as short bones due to their small size and shape. Short bones like fingers are essential for providing dexterity and precise movements rather than supporting weight or acting as levers for movement. Therefore, the correct answer is D, Fingers, as they are not classified as long bones.

2. Which of the following statements regarding the pericardium is not correct?

A. It allows for the heart to work in a relatively friction-free environment
B. It is a single-walled layer around the heart
C. It prevents overfilling of the heart with blood
D. It protects and anchors the heart

Correct answer: B

Rationale: The correct statement about the pericardium is that it is double-walled, not single-walled. Choice A is correct because the pericardium does allow the heart to work in a relatively friction-free environment, reducing friction during heartbeats. Choice C is correct as the pericardium helps prevent the overfilling of the heart with blood. Choice D is also correct as the pericardium serves to protect and anchor the heart in place within the chest cavity.

3. What is the action of the triceps reflex?

A. Forces contraction of the triceps and extension of the arm.
B. Forces contraction of the biceps, relaxation of the biceps, and arm extension.
C. Causes the triceps to contract, causing the forearm to supinate and flex.
D. Causes the triceps to relax and the upper arm to pronate and extend.

Correct answer: A

Rationale: The triceps reflex causes the triceps muscle to contract, leading to the extension of the arm. This reflex is a protective response to sudden stretching of the triceps muscle, as seen when a physician taps the triceps tendon during a physical examination. Choice A is the correct answer as it accurately reflects the action of the triceps reflex. Choices B, C, and D are incorrect because they describe actions that are not associated with the triceps reflex. Biceps contraction, forearm supination, flexion, triceps relaxation, and pronation are not part of the triceps reflex arc.

4. Which of the following is NOT a function of the nervous system?

A. Detecting touch
B. Regulating body temperature
C. Producing insulin
D. Controlling muscle movement

Correct answer: C

Rationale: The nervous system is responsible for detecting touch (option A), regulating body temperature (option B), and controlling muscle movement (option D). Producing insulin (option C) is a function of the endocrine system, which produces hormones like insulin to regulate metabolism and glucose levels. Therefore, option C is the correct answer as it is not a function of the nervous system.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

A. 18.3 g
B. 19.7 g
C. 21.0 g
D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.