ATI TEAS 7
ATI TEAS Science Test
1. Long bones are one of the five major types of bones in the human body. All of the following bones are long bones, EXCEPT
- A. Thighs
- B. Forearms
- C. Ankles
- D. Fingers
Correct answer: D
Rationale: Long bones are one of the five major types of bones in the human body, characterized by their elongated shape. Thighs, forearms, and ankles are examples of long bones as they are longer than they are wide and have a tubular structure, aiding in support and movement. Fingers, however, are categorized as short bones due to their small size and shape. Short bones like fingers are essential for providing dexterity and precise movements rather than supporting weight or acting as levers for movement. Therefore, the correct answer is D, Fingers, as they are not classified as long bones.
2. Which of the following is NOT a type of asexual reproduction in bacteria?
- A. Binary fission
- B. Conjugation
- C. Budding
- D. Transduction
Correct answer: D
Rationale: A) Binary fission: This is a common method of asexual reproduction in bacteria where a single cell divides into two identical daughter cells. B) Conjugation: This is a process in which genetic material is transferred between bacterial cells through direct cell-to-cell contact, leading to genetic recombination. C) Budding: Budding is a form of asexual reproduction where a new organism develops from an outgrowth or bud on the parent organism. D) Transduction: Transduction is a method of horizontal gene transfer in bacteria where genetic material is transferred from one bacterium to another by a bacteriophage (a virus that infects bacteria). It is not a form of asexual reproduction in bacteria. Therefore, the correct answer is D) Transduction, as it is not a type of asexual reproduction in bacteria but a mechanism of genetic exchange.
3. How many grams of solid CaCO3 are needed to make 600 mL of a 35 M solution? The atomic masses for the elements are as follows: Ca = 40.1 g/mol; C = 12.01 g/mol; O = 16.00 g/mol.
- A. 18.3 g
- B. 19.7 g
- C. 21.0 g
- D. 24.2 g
Correct answer: B
Rationale: 1. First, calculate the molar mass of CaCO3 by adding the atomic masses of Ca, C, and 3 O atoms: 40.1 + 12.01 + (3 * 16.00) = 100.13 g/mol. 2. Calculate the number of moles in 600 mL of a 35 M solution: 600 mL * 35 mol/L = 21,000 mmol. 3. Convert moles to grams using the molar mass of CaCO3: 21,000 mmol * (100.13 g/mol / 1000 mmol/mol) = 2,102.73 g. 4. Therefore, you would need 19.7 g of solid CaCO3 to make 600 mL of a 35 M solution.
4. Which of the following describes the difference between prokaryotic and eukaryotic cells?
- A. Prokaryotic cells have a nucleus, while eukaryotic cells don't.
- B. Eukaryotic cells are simpler in structure than prokaryotic cells.
- C. Prokaryotic cells have membrane-bound organelles, while eukaryotic cells don't.
- D. Eukaryotic cells have a true nucleus and membrane-bound organelles, while prokaryotic cells lack these.
Correct answer: D
Rationale: Eukaryotic cells have a true nucleus that contains the genetic material, while prokaryotic cells lack a true nucleus. Eukaryotic cells also have membrane-bound organelles such as mitochondria, endoplasmic reticulum, and Golgi apparatus, which are absent in prokaryotic cells.
5. What is the process of transporting molecules across the cell membrane against a concentration gradient called?
- A. Diffusion
- B. Osmosis
- C. Active transport
- D. Facilitated diffusion
Correct answer: C
Rationale: A) Diffusion is the movement of molecules from an area of higher concentration to an area of lower concentration, which does not require energy input. B) Osmosis is the movement of water molecules across a selectively permeable membrane from an area of lower solute concentration to an area of higher solute concentration. C) Active transport is the process of transporting molecules across the cell membrane against a concentration gradient, requiring energy in the form of ATP to move substances from an area of lower concentration to an area of higher concentration. D) Facilitated diffusion is a type of passive transport that involves the use of transport proteins to move molecules across the cell membrane from an area of higher concentration to an area of lower concentration, without the need for energy input.
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