if you have a rectangle with width 5 inches and length 10 inches and scale it by a factor of 2 what will the new perimeter be
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ATI TEAS 7

TEAS Math Questions

1. If you have a rectangle with a width of 5 inches and a length of 10 inches and scale it by a factor of 2, what will the new perimeter be?

Correct answer: C

Rationale: When a rectangle is scaled by a factor of 2, both the length and width are multiplied by 2. The new dimensions become width = 5 * 2 = 10 inches and length = 10 * 2 = 20 inches. Therefore, the new perimeter is calculated as 2 * (10 + 20) = 60 inches. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on scaling the dimensions of the rectangle.

2. When the sampling distribution of means is plotted, which of the following is true?

Correct answer: A

Rationale: When the sampling distribution of means is plotted, the distribution tends to be approximately normal, especially as the sample size increases. This phenomenon is described by the Central Limit Theorem, which states that the sampling distribution of the sample mean will be normally distributed regardless of the shape of the original population distribution as long as the sample size is sufficiently large. Choices B and C are incorrect because sampling distributions of means are not skewed. Choice D is incorrect because there is a predictable shape to the distribution, which is approximately normal.

3. Mathew has to earn more than 96 points on his high school entrance exam in order to be eligible for varsity sports. Each question is worth 3 points, and the test has a total of 40 questions. Let x represent the number of test questions. How many questions can Mathew answer incorrectly and still qualify for varsity sports?

Correct answer: C

Rationale: To determine the number of correct answers Mathew needs, solve the inequality: 3x > 96. This simplifies to x > 32. Therefore, Mathew must answer more than 32 questions correctly to qualify for varsity sports. Since the test consists of 40 questions, he can afford to answer at most 40 - 32 = 8 questions incorrectly. Therefore, the correct answer is 0 ≤ x < 8. Option A (x > 32) is incorrect as it suggests Mathew needs to answer more than 32 questions correctly, which is not the case. Option B (x > 8) is also incorrect as it does not account for the total number of questions in the test. Option D (0 ≤ x ≤ 8) is incorrect as it includes the possibility of answering all questions incorrectly, which is not allowed for Mathew to qualify for varsity sports.

4. A commuter survey counts the people riding in cars on a highway in the morning. Each car contains only one man, only one woman, or both one man and one woman. Out of 25 cars, 13 contain a woman and 20 contain a man. How many contain both a man and a woman?

Correct answer: C

Rationale: Let's denote the number of cars containing only a man as M, only a woman as W, and both a man and a woman as B. Given that there are 25 cars in total, we have: M + W + B = 25 From the information provided, we know that 13 cars contain a woman (W) and 20 cars contain a man (M). Since each car contains either one man, one woman, or both, the cars that contain both a man and a woman (B) are counted once in each of the M and W categories. Therefore, to find out how many cars contain both a man and a woman, we need to subtract the number of cars that contain only a man and only a woman from the total cars. M + B = 20 (as 20 cars contain a man) W + B = 13 (as 13 cars contain a woman) Solving the above two equations simultaneously, we get: M = 12, W = 5, B = 8 Therefore, 8 cars contain both a man and a woman. Hence, the correct answer is 8. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on the information provided.

5. Solve for x: 2x - 7 = 3

Correct answer: D

Rationale: To solve the equation for x, follow these steps: 2x - 7 = 3. Add 7 to both sides to isolate 2x, resulting in 2x = 10. Then, divide by 2 on both sides to find x, which gives x = 5. Therefore, the correct answer is x = 5. Choices A, B, and C are incorrect because they do not accurately solve the equation.

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