if you have a rectangle with width 5 inches and length 10 inches and scale it by a factor of 2 what will the new perimeter be
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ATI TEAS 7

TEAS Math Questions

1. If you have a rectangle with a width of 5 inches and a length of 10 inches and scale it by a factor of 2, what will the new perimeter be?

Correct answer: C

Rationale: When a rectangle is scaled by a factor of 2, both the length and width are multiplied by 2. The new dimensions become width = 5 * 2 = 10 inches and length = 10 * 2 = 20 inches. Therefore, the new perimeter is calculated as 2 * (10 + 20) = 60 inches. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on scaling the dimensions of the rectangle.

2. Solve for x: 2x - 7 = 3

Correct answer: D

Rationale: To solve the equation for x, follow these steps: 2x - 7 = 3. Add 7 to both sides to isolate 2x, resulting in 2x = 10. Then, divide by 2 on both sides to find x, which gives x = 5. Therefore, the correct answer is x = 5. Choices A, B, and C are incorrect because they do not accurately solve the equation.

3. Jerry needs to load four pieces of equipment onto a factory elevator that has a weight limit of 800 pounds. Jerry weighs 200 pounds. What would be the average weight of each item so that the elevator's weight limit is not exceeded?

Correct answer: B

Rationale: To find the average weight per item, subtract Jerry's weight from the elevator's weight limit: 800 - 200 = 600 pounds. Since there are 4 items, divide 600 by 4 to determine that each item should weigh 150 pounds. Choice A (128 pounds), C (175 pounds), and D (180 pounds) are incorrect as they do not correctly calculate the average weight per item to ensure the elevator's weight limit is not exceeded.

4. Which of the following best describes the relationship in this set of data?

Correct answer: B

Rationale: The correct answer is 'B: Low positive correlation.' In a low positive correlation, the variables tend to increase together, but the relationship is not strong. This description fits the data set provided. Choice A, 'High positive correlation,' is incorrect because the correlation is not strong. Choice C, 'Low negative correlation,' is incorrect as the variables are not decreasing together. Choice D, 'No correlation,' is incorrect because there is a relationship between the variables, albeit weak.

5. Between the years 2000 and 2010, the number of births in the town of Daneville increased from 1432 to 2219. What is the approximate percent increase in the number of births?

Correct answer: A

Rationale: To calculate the percent increase, subtract the initial value from the final value, which gives 2219 - 1432 = 787. Then, divide the increase (787) by the initial value (1432) and multiply by 100 to get the percentage: (787/1432) * 100 = 55%. Therefore, the approximate percent increase in the number of births is 55%. Choice B, 36%, is incorrect because it does not match the calculated increase. Choice C, 64%, is incorrect as it is higher than the actual percentage. Choice D, 42%, is incorrect as it is lower than the actual percentage.

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