how many grams of solid caco3 are needed to make 600 ml of a 035 m solution the atomic masses for the elements are as follows ca 4007 gmol c 1201 gm

ATI TEAS 7

Science TEAS Practice Test

1. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

A. 18.3 g
B. 19.7 g
C. 21.0 g
D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

2. During which stage of meiosis II are sister chromatids separated, resulting in four genetically unique daughter cells?

A. Prophase I
B. Prophase II
C. Anaphase I
D. Anaphase II

Correct answer: D

Rationale: - Prophase I occurs in meiosis I, not meiosis II. During Prophase I, homologous chromosomes pair up and exchange genetic material in a process called crossing over. - Prophase II is the stage where the nuclear envelope breaks down, and spindle fibers start to reappear, preparing the cell for division. Sister chromatids are still attached during Prophase II. - Anaphase I is the stage in meiosis I where homologous chromosomes are separated and pulled to opposite poles of the cell. - Anaphase II is the stage in meiosis II where sister chromatids are separated and pulled to opposite poles of the cell, resulting in four genetically unique daughter cells. This is the stage where the final separation of genetic material occurs, leading to the formation of haploid daughter cells.

3. Dysentery is an infectious disease caused by which type of microbe?

A. Helminth
B. Bacteria
C. Protozoan
D. Fungus

Correct answer: B

Rationale: The correct answer is B: Bacteria. Dysentery is typically caused by bacterial infections, such as Shigella, Campylobacter, or Escherichia coli. While parasites and protozoa can also cause similar symptoms, bacterial infections are the most common causes of dysentery. Choice A (Helminth) is incorrect as helminths are parasitic worms that typically cause different types of infections. Choice C (Protozoan) is incorrect as some protozoa like Entamoeba histolytica can cause dysentery, but bacterial infections are more common. Choice D (Fungus) is incorrect as fungal infections do not typically cause dysentery.

4. Which statement is true regarding aromatic compounds?

A. Contain a ring structure with alternating single and double bonds
B. Readily undergo addition reactions
C. Are easily broken down by water
D. Do not contain any pi (Ï€) bonds

Correct answer: A

Rationale: Aromatic compounds contain a ring structure with alternating single and double bonds, known as a benzene ring. This alternating pattern of bonds gives aromatic compounds their stability and unique properties. Due to this resonance, aromatic compounds are less reactive towards addition reactions. Water does not easily break down aromatic compounds due to their stability from the delocalized electrons in the ring structure. Therefore, the correct statement is that aromatic compounds contain a ring structure with alternating single and double bonds, providing them with stability and unique properties. Choices B, C, and D are incorrect. Aromatic compounds do not readily undergo addition reactions (B), are not easily broken down by water (C), and do contain pi (Ï€) bonds due to the presence of the alternating single and double bonds in the ring structure (D).

5. Which of the following bones is part of the axial skeleton?

A. Femur
B. Humerus
C. Skull
D. Pelvis

Correct answer: C

Rationale: The correct answer is C: Skull. The axial skeleton consists of bones along the body's central axis, including the skull, vertebral column, ribs, and sternum. Choices A, B, and D are incorrect because the femur, humerus, and pelvis are part of the appendicular skeleton, which comprises the bones of the limbs and girdles.