Nursing Elites

1. How does asexual reproduction differ from sexual reproduction?

• A. asexual reproduction results in all cells being identical to the original cell; sexual reproduction results in half of the cells being identical to the original cell
• B. asexual reproduction results in two cells that contribute genetic material to daughter cells, resulting in significantly greater variation
• C. sexual reproduction involves two cells that contribute genetic material to daughter cells, resulting in significantly greater variation
• D. sexual reproduction involves one cell that yields all cells produced to be identical

Correct answer: C

Rationale: Sexual reproduction involves two cells (gametes) that contribute genetic material to daughter cells, resulting in significantly greater genetic variation in the offspring. This genetic variation is essential for evolution and adaptation to environmental changes. In contrast, asexual reproduction involves one cell dividing to produce offspring that are genetically identical to the parent cell. Choice A is incorrect because sexual reproduction does not result in half of the cells being identical to the original cell; it involves two cells contributing genetic material. Choice B is incorrect because asexual reproduction does not result in significantly greater variation; it produces genetically identical offspring. Choice D is incorrect because sexual reproduction involves two cells contributing genetic material, not one cell yielding all identical cells.

2. If a test has poor internal consistency, which statement is true?

• A. The test produces different results at different times.
• B. The items do not correlate or measure similar things.
• C. The test produces different results depending on the researcher.
• D. The items never vary even when the test environment changes.

Correct answer: B

Rationale: Correct answer: If a test has poor internal consistency, it means that the items do not correlate or measure similar things. This lack of correlation indicates that the items in the test are not measuring the same underlying construct or concept, leading to unreliable results. Choice A is incorrect because poor internal consistency is not about producing different results at different times but rather about the lack of correlation among items. Choice C is incorrect because the issue lies within the test itself, not with different researchers. Choice D is incorrect because poor internal consistency implies that the items do vary in their measurement, contributing to the unreliability of the test.

3. What are the two catabolic pathways that lead to cellular energy production?

• A. Fermentation and internal respiration
• B. Fermentation and external respiration
• C. Fermentation and cellular respiration
• D. Fermentation and anaerobic respiration

Correct answer: C

Rationale: The correct answer is 'Fermentation and cellular respiration.' Fermentation is an anaerobic catabolic process that occurs in the absence of oxygen, producing limited amounts of ATP. Cellular respiration, on the other hand, is the aerobic catabolic pathway that occurs in the presence of oxygen and is the most efficient way of producing ATP. Choices A, B, and D are incorrect because internal respiration, external respiration, and anaerobic respiration are not the correct pathways leading to cellular energy production.

4. What is the first step in the conversion of glucose to pyruvate?

• A. Glycolysis
• B. Krebs cycle
• C. Electron transport chain
• D. Aerobic respiration

Correct answer: A

Rationale: The correct answer is Glycolysis. Glycolysis is the initial step in the conversion of glucose to pyruvate. During glycolysis, glucose is broken down into pyruvate through a series of enzymatic reactions. Choice B, the Krebs cycle, occurs after glycolysis in aerobic cellular respiration. Choice C, the Electron transport chain, is the final step in aerobic respiration where the majority of ATP is produced. Choice D, Aerobic respiration, is a broader term that encompasses glycolysis, the Krebs cycle, and the electron transport chain, but it is not the specific first step in the conversion of glucose to pyruvate.

5. Huntington’s disease is carried on the dominant allele. In a situation where two heterozygous parents have the disease, what percentage of their offspring are predicted to be disease-free?

• A. 0%
• B. 25%
• C. 50%
• D. 100%

Correct answer: B

Rationale: In this scenario, both parents are heterozygous for Huntington's disease, meaning each carries one dominant allele (representing the disease) and one recessive allele (representing no disease). When they have offspring, there is a 25% chance that each child will inherit two recessive alleles, making them disease-free. The Punnett square for two heterozygous parents (Hh x Hh) yields a 25% probability of offspring being homozygous recessive (hh) and therefore disease-free. Choice A (0%) is incorrect because there is a possibility of disease-free offspring. Choice C (50%) is incorrect as it represents the likelihood of being a carrier. Choice D (100%) is incorrect as all offspring will not be disease-free in this scenario.

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