Nursing Elites

1. Histograms use ________, and bar graphs do not.

• A. Ranges
• B. Categories
• C. Labels
• D. Percentages

Correct answer: A

Rationale: Correct Answer: Ranges. Histograms utilize ranges (intervals) to display the frequency distribution of continuous data, highlighting the frequency of values falling within each interval. Bar graphs, on the other hand, represent discrete data using separate and distinct bars to show comparisons between different categories or groups. Choice B (Categories) is incorrect because both histograms and bar graphs can display data based on categories, but histograms use ranges to group continuous data. Choice C (Labels) is incorrect as both types of graphs can have labels to provide context and information. Choice D (Percentages) is incorrect because percentages can be used in both histograms and bar graphs to show proportions, but they are not a defining feature that distinguishes histograms from bar graphs.

2. What is the value of b in this equation? 5b - 4 = 2b + 17

• A. 13
• B. 24
• C. 7
• D. 21

Correct answer: C

Rationale: To find the value of b in the equation 5b - 4 = 2b + 17, you need to first simplify the equation. By subtracting 2b from both sides of the equation and adding 4 to both sides, you get 3b = 21. Then, dividing both sides of the equation by 3 gives you b = 7. Therefore, the value of b is 7, which corresponds to option C. Choice A (13) is incorrect as it does not match the correct calculation. Choice B (24) is incorrect as it is not the result of the correct algebraic manipulation. Choice D (21) is incorrect as it is not the value of b obtained after solving the equation step by step.

3. Robert secures three new clients every eight months. After how many months has he secured 24 new clients?

• A. 64
• B. 58
• C. 52
• D. 66

Correct answer: C

Rationale: To determine the number of months it takes for Robert to secure 24 new clients, we set up a proportion: 3 clients / 8 months = 24 clients / x months. Cross multiplying gives 3x = 8 * 24. Solving for x results in x = 64 / 3 = 52. Therefore, after 52 months, Robert has secured 24 new clients. Choice A (64) is incorrect as it miscalculates the solution. Choices B (58) and D (66) are also incorrect as they do not reflect the accurate calculation based on the given information.

4. A lab technician took 500 milliliters of blood from a patient. The technician used 1/6 of the blood for further tests. How many milliliters of blood were used for further tests? Round your answer to the nearest hundredth.

• A. 83
• B. 83.3
• C. 83.33
• D. 83.34

Correct answer: C

Rationale: To find 1/6 of 500, multiply 500 by 1/6: (500)(1/6) = 500/6 = 83.33. Converting the fraction to a decimal gives 83.33. Rounding this to the nearest hundredth results in 83.33. Therefore, 83.33 milliliters of blood were used for further tests. Choice A is incorrect as it does not consider the decimal value of the fraction. Choice B is incorrect as it rounds to the tenths place, not the nearest hundredth. Choice D is incorrect as it rounds up unnecessarily, as the correct answer should be rounded to 83.33.

5. Curtis measured the temperature of water in a flask in his science class. The temperature of the water was 35 °C. He carefully heated the flask so that the temperature of the water increased by about 2 °C every 3 minutes. Approximately how much had the temperature of the water increased after 20 minutes?

• A. 10 °C
• B. 13 °C
• C. 15 °C
• D. 35 °C

Correct answer: B

Rationale: To find the increase in temperature after 20 minutes, calculate how many 3-minute intervals are in 20 minutes (20 ÷ 3 = 6.66, rounding to 7 intervals). Then, multiply the temperature increase per interval (2 °C) by the number of intervals (7 intervals), giving a total increase of 14 °C. Therefore, after 20 minutes, the temperature of the water would have increased by approximately 14 °C. Choice A, 10 °C, is incorrect as it underestimates the total increase. Choice C, 15 °C, is incorrect as it overestimates the total increase. Choice D, 35 °C, is incorrect as it represents the initial temperature of the water, not the increase in temperature.

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