ATI TEAS 7
ATI TEAS Math Practice Test
1. If Stella's current weight is 56 kilograms, which of the following is her approximate weight in pounds? (Note: 1 kilogram is approximately equal to 2.2 pounds.)
- A. 123 pounds
- B. 110 pounds
- C. 156 pounds
- D. 137 pounds
Correct answer: A
Rationale: To convert Stella's weight from kilograms to pounds, you multiply her weight in kilograms (56) by the conversion factor (2.2): 56 × 2.2 = 123.2 pounds. Since we need to find the approximate weight in pounds, the closest option is 123 pounds, making choice A the correct answer. Choices B, C, and D are incorrect because they do not reflect the accurate conversion of Stella's weight from kilograms to pounds.
2. What is the area of a rectangle with a length of 5 cm and a width of 4 cm?
- A. 9 cm²
- B. 20 cm²
- C. 10 cm²
- D. 25 cm²
Correct answer: B
Rationale: To find the area of a rectangle, you multiply its length by its width. In this case, the length is 5 cm and the width is 4 cm. So, Area = length * width = 5 cm * 4 cm = 20 cm². Therefore, the correct answer is 20 cm². Choice A (9 cm²), Choice C (10 cm²), and Choice D (25 cm²) are incorrect as they do not result from the correct calculation of multiplying the length and width of the rectangle.
3. Simplify the expression. Which of the following is correct? (52(3) + 3(-2)^2 / 4 + 3^2 - 2(5 - 8))
- A. 9/8
- B. 87/19
- C. 9
- D. 21/2
Correct answer: B
Rationale: To simplify the expression, apply the order of operations (PEMDAS). Begin by squaring -2 to get 4. Then perform the multiplication and subtraction within parentheses: 52(3) + 3(4)/4 + 9 - 2(5 - 8) = 156 + 12/4 + 9 - 2(3) = 156 + 3 + 9 - 6 = 168 + 3 - 6 = 171 - 6 = 165. Therefore, the correct simplified expression is 165, which is equivalent to 87/19. Choices A, C, and D are incorrect because they do not represent the accurate simplification of the given expression.
4. Which of the following describes a graph that represents a proportional relationship?
- A. The graph has a slope of 2,500 and a y-intercept of 250
- B. The graph has a slope of 1,500 and a y-intercept of -150
- C. The graph has a slope of 2,000 and a y-intercept of 0
- D. The graph has a slope of -1,800 and a y-intercept of -100
Correct answer: C
Rationale: A graph that has a y-intercept of 0 indicates a proportional relationship because the starting value is 0, and no amount is added to or subtracted from the term containing the slope. In this case, choice C is correct as it has a y-intercept of 0, which aligns with the characteristics of a proportional relationship. Choices A, B, and D have non-zero y-intercepts, indicating a starting value other than 0, which does not represent a proportional relationship.
5. Kimberley earns $10 an hour babysitting, and after 10 p.m., she earns $12 an hour, with the amount paid being rounded to the nearest hour accordingly. On her last job, she worked from 5:30 p.m. to 11 p.m. In total, how much did Kimberley earn on her last job?
- A. $45
- B. $57
- C. $62
- D. $42
Correct answer: C
Rationale: Kimberley worked from 5:30 p.m. to 11 p.m., which is a total of 5.5 hours before 10 p.m. (from 5:30 p.m. to 10 p.m.) and 1 hour after 10 p.m. The earnings she made before 10 p.m. at $10 an hour was 5.5 hours * $10 = $55. Her earnings after 10 p.m. for the rounded hour were 1 hour * $12 = $12. Therefore, her total earnings for the last job were $55 + $12 = $67. Since the amount is rounded to the nearest hour, the closest rounded amount is $62. Therefore, Kimberley earned $62 on her last job. Choice A is incorrect as it does not consider the additional earnings after 10 p.m. Choices B and D are incorrect as they do not factor in the hourly rates and the total hours worked accurately.
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