Nursing Elites

1. What is the probability of consecutively pulling two more orange blocks, without replacement, from a bag containing 3 orange blocks, 5 green blocks, and 4 purple blocks?

• A. 3/12
• B. 3/55
• C. 2/10
• D. 1/3

Correct answer: B

Rationale: To calculate the probability of consecutively pulling two more orange blocks without replacement, we first determine the probability of pulling an orange block on the first draw, which is 3/12 (3 orange blocks out of 12 total blocks). After removing one orange block, there are only 11 blocks left, so the probability of pulling another orange block on the second draw is 2/11. To find the combined probability, we multiply the probabilities together: (3/12) * (2/11) = 6/132 = 3/55. Therefore, the correct answer is B. Choice A (3/12) incorrectly simplifies the probability before calculating the second draw. Choice C (2/10) does not consider the specific number of orange blocks in the bag. Choice D (1/3) does not account for the reduced number of blocks after the first draw.

2. The second midwife allocates 1/2 of her funds to pay an office administrator, plus another 1/10 for office supplies. What is the total fraction of the second midwife's budget that is spent on the office administrator and office supplies?

• A. 3/5
• B. 2/12
• C. 2/20
• D. 1/20

Correct answer: A

Rationale: To find the total fraction of the second midwife's budget spent on the office administrator and office supplies, add the fractions. The midwife allocates 1/2 of her funds to the office administrator (1/2) and another 1/10 for office supplies. Adding 1/2 and 1/10 gives a total of 3/5. Choice A (3/5) is correct. Choice B (2/12) is incorrect as it simplifies to 1/6, which is not the total fraction. Choice C (2/20) is incorrect as it simplifies to 1/10, which is only the fraction spent on office supplies, not the total. Choice D (1/20) is incorrect as it represents only the fraction spent on office supplies, not the total spent on both the administrator and supplies.

3. Solve the equation 3(2x+5)=11x+5 for x. Which of the following is correct?

• A. 1
• B. 2
• C. -1
• D. -2

Correct answer: B

Rationale: To solve the equation, distribute 3 to both terms inside the parentheses: 6x + 15 = 11x + 5. Then, move 11x to the left side by subtracting it from both sides: 6x - 11x = 5 - 15. Simplify to get -5x = -10. Divide by -5 to isolate x: x = 2. Therefore, the correct answer is x = 2. Choices A, C, and D are incorrect because they do not match the correct solution obtained by solving the equation step by step.

4. Simplify the expression. Which of the following is the value of x? (5(4x – 5) = (3/2)(2x – 6))

• A. −(2/7)
• B. −(4/17)
• C. (16/17)
• D. (8/7)

Correct answer: C

Rationale: To solve the given proportion 5(4x – 5) = (3/2)(2x – 6), first distribute to get 20x - 25 = 3x - 9. Then, simplify the linear equation by isolating x: 20x - 3x = 25 - 9, which leads to 17x = 16. Finally, solving for x gives x = 16/17. Choice A is incorrect as it does not match the calculated value of x. Choice B is incorrect as it does not correspond to the correct solution for x. Choice D is incorrect as it does not align with the accurate value of x obtained from solving the equation.

5. When the weights of the newborn babies are graphed, the distribution of weights is symmetric with the majority of weights centered around a single peak. Which of the following describes the shape of this distribution?

• A. Uniform
• B. Bimodal
• C. Bell-shaped
• D. Skewed right

Correct answer: C

Rationale: The correct answer is C: Bell-shaped. A symmetric distribution with a single peak is characteristic of a bell-shaped distribution, also known as a normal distribution. This distribution forms a symmetrical, bell-like curve when graphed. Choice A, 'Uniform,' would describe a distribution where all values have equal probability. Choice B, 'Bimodal,' would indicate a distribution with two distinct peaks. Choice D, 'Skewed right,' suggests a distribution where the tail on the right side is longer or more pronounced, unlike the symmetrical bell-shaped distribution described in the question.

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