Nursing Elites

1. Erma has her eye on two sweaters at her favorite clothing store, but she has been waiting for the store to offer a sale. This week, the store advertises 25% off a second item of equal or lesser value. One sweater is $50, and the other is $44. What will Erma spend?

• A. $79
• B. $81
• C. $83
• D. $85

Correct answer: C

Rationale: Erma receives a 25% discount on the $44 sweater, which amounts to a $11 discount. Therefore, she pays $44 - $11 = $33 for this sweater. Adding this discounted price to the $50 sweater, Erma will spend a total of $50 + $33 = $83. Choice A, $79, is incorrect because it does not include the correct calculation for the discounted sweater. Choice B, $81, is incorrect as it does not consider the discounts on both sweaters. Choice D, $85, is incorrect since it overestimates the total amount Erma will spend.

2. During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?

• A. shifts = 20 + 3 + 1/2
• B. shifts = (20)(3)(1/2)
• C. shifts = (20)(3) + 1/2
• D. shifts = 20 + (3)(1/2)

Correct answer: B

Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.

3. What is the approximate metric equivalent of 7 inches?

• A. 3.2 cm
• B. 2.8 cm
• C. 15.4 cm
• D. 17.8 cm

Correct answer: D

Rationale: The correct answer is D: 17.8 cm. To convert inches to centimeters, you can use the conversion factor 1 inch = 2.54 cm. Therefore, 7 inches is equal to 7 * 2.54 = 17.78 cm, which rounds to 17.8 cm. Choices A, B, and C are incorrect because they do not correspond to the correct conversion of 7 inches to centimeters.

4. What is the least common multiple? What is the least common factor?

• A. The smallest number that both numbers multiply into; the smallest number that divides evenly into both
• B. The largest number that both numbers multiply into; the smallest number that divides evenly into both
• C. The smallest number that both numbers divide into evenly; the smallest number that multiplies into both
• D. The smallest number that both numbers divide into evenly; the smallest number that both multiply into

Correct answer: A

Rationale: The least common multiple is the smallest number that both numbers multiply into, which means it is the smallest number that both numbers can be evenly divided by without leaving a remainder. The least common factor, on the other hand, is the smallest number that divides both numbers without leaving a remainder. Therefore, choice A is correct as it accurately defines the least common multiple and factor. Choices B, C, and D are incorrect because they provide inaccurate definitions or mix up the concepts of multiplication and division in relation to finding the least common multiple and factor.

5. What is the volume of a ball with a diameter of 7 inches?

• A. 165.7 in³
• B. 179.6 in³
• C. 184.5 in³
• D. 192.3 in³

Correct answer: A

Rationale: To find the volume of a sphere, the formula V = (4/3)πr³ is used, where r is the radius of the sphere. Given that the diameter of the ball is 7 inches, the radius (r) would be half of the diameter, which is 3.5 inches. Plugging this value into the formula: V = (4/3)π(3.5)³ = (4/3)π(42.875) ≈ 165.7 in³. Therefore, the correct answer is A. Choice B, C, and D are incorrect as they do not accurately represent the volume of the ball with a diameter of 7 inches.

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