Nursing Elites

1. Margery plans a vacation with costs for airfare, hotel (5 nights), sightseeing, and meals. If she receives a 10% discount on additional hotel nights, what will she spend?

• A. 1328.35
• B. 1373.5
• C. 1381.4
• D. 1417.6

Correct answer: A

Rationale: To calculate Margery's total cost, we first need to find the cost without the discount. Let's say the original cost is x. With a 10% discount, she saves 10% of the cost of additional hotel nights. Since she is staying for 5 nights, the discount applies to 4 additional nights (5 - 1 night already included). Therefore, she saves 10% of 4 nights' cost. If x is the cost of 1 night, the total cost without discount is 5x. With the 10% discount, she saves 0.1 * 4x = 0.4x. So, the cost after discount is 5x - 0.4x = 4.6x. Given that the total cost is 5x for 5 nights, we can equate 5x to 4.6x to find x. Solving for x, we get x = Total cost / 5 = 5x / 5 = 4.6x / 5. Therefore, x = 4.6x / 5, which simplifies to x = 0.92 * 5x. This means 1 night's cost is 0.92 times the total cost for 5 nights. Given the total cost is $1328.35, we find the cost for 1 night is $1328.35 / 5 = $265.67. So, Margery will spend $1328.35 for her vacation.

2. Jayden rides his bike for 5/8 miles. He takes a break and rides another 3/4 miles. How many miles does he ride?

• A. 1 3/8 miles
• B. 1 1/2 miles
• C. 1 7/8 miles
• D. 2 miles

Correct answer: A

Rationale: To find the total distance Jayden rides, you need to add the fractions 5/8 + 3/4. To add these fractions, you must ensure they have a common denominator. In this case, the common denominator is 8. So, 5/8 + 3/4 = 5/8 + 6/8 = 11/8. Since 11/8 can be simplified to 1 3/8, Jayden rides a total of 1 3/8 miles. Choice B (1 1/2 miles), Choice C (1 7/8 miles), and Choice D (2 miles) are incorrect as they do not accurately represent the total distance calculated by adding the two fractions, which is 1 3/8 miles.

3. A recipe calls for 5.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?

• A. 10.2 mL
• B. 12 mL
• C. 7.43 mL
• D. 27 mL

Correct answer: D

Rationale: To convert the amount of vanilla from teaspoons to milliliters, we multiply the number of teaspoons by the conversion factor of 4.93 mL/teaspoon. 5.5 teaspoons * 4.93 mL/teaspoon = 27.115 mL, which rounds to 27 mL. Therefore, the correct amount of vanilla in mL is 27 mL. Choice A (10.2 mL), Choice B (12 mL), and Choice C (7.43 mL) are incorrect as they do not correctly convert the given amount of teaspoons to milliliters based on the provided conversion factor.

4. Which of the following best describes the data set below? 1, 1, 2, 2, 2, 2, 3, 3, 7, 7, 8, 8, 8, 8, 9, 9

• A. Uniform
• B. Right-skewed
• C. Bimodal
• D. Left-skewed

Correct answer: C

Rationale: The correct answer is C: Bimodal. A bimodal distribution has two distinct peaks or modes. In this data set, the numbers 2 and 8 appear more frequently than other numbers, creating two modes (2 and 8). Choices A, B, and D are incorrect. Option A, 'Uniform,' describes a distribution where all values have equal frequency, which is not the case in this data set. Options B and D, 'Right-skewed' and 'Left-skewed,' refer to distributions where the data is skewed towards one side, which is not observed in this dataset. Therefore, the data set is best described as bimodal.

5. A recipe calls for 0.375 cups of sugar, but you only want to make 0.625 of the recipe. How much sugar should you use?

• A. 1.125 cups
• B. 1.111 cups
• C. 0.6 cups
• D. 2.4 cups

Correct answer: C

Rationale: To find out how much sugar should be used when making 0.625 of the recipe, you need to multiply 0.375 (amount required for the full recipe) by 0.625 (proportion of the recipe you want to make). 0.375 * 0.625 = 0.234375. Therefore, you should use 0.234375 cups of sugar, which is equivalent to 0.6 cups. This is the correct answer. Choices A, B, and D are incorrect because they do not correctly calculate the adjusted amount of sugar needed based on the proportion of the recipe being made.

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