Nursing Elites

1. In a study on anorexia, 100 patients participated. Among them, 70% were women, and 10% of the men were overweight as children. How many male patients in the study were not overweight as children?

• A. 3
• B. 10
• C. 27
• D. 30

Correct answer: C

Rationale: Out of the 100 patients, 30% were men. Since 10% of the men were overweight as children, 90% of the male patients were not overweight. Therefore, the number of male patients not overweight as children can be calculated as 30 (total male patients) x 0.90 = 27. Choices A, B, and D are incorrect because they do not accurately calculate the number of male patients who were not overweight as children based on the given information.

2. A student gets 42 questions out of 48 correct on a quiz. What is the percentage of questions that the student answered correctly?

• A. 1.14%
• B. 82.50%
• C. 85.00%
• D. 87.50%

Correct answer: D

Rationale: To find the percentage of questions answered correctly, divide the number of correct questions by the total number of questions: 42/48 = 0.875. Multiply the result by 100 to express it as a percentage, which gives 87.5%. Therefore, the correct answer is 87.50%. Choice A (1.14%) is incorrect as it does not reflect the correct percentage. Choices B (82.50%) and C (85.00%) are also incorrect as they do not align with the calculation based on the given information.

3. Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?

• A. $1.75
• B. $2.00
• C. $2.25
• D. $2.50

Correct answer: C

Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25. Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.

4. One roommate is saving to buy a house, so each month, he puts money aside in a special house savings account. The ratio of his monthly house savings to his rent is 1:3. If he pays $270 per month in rent, how much money does he put into his house savings account each month?

• A. $90
• B. $270
• C. $730
• D. $810

Correct answer: A

Rationale: The ratio of his savings to his rent is 1:3, which means that for every $3 he pays in rent, he saves $1 for the purchase of a house. To calculate the amount saved, divide $270 by 3: $270 ÷ 3 = $90. Therefore, he puts $90 into his house savings account each month. Choice B, $270, is incorrect because that is the amount he pays in rent, not the amount saved. Choices C and D, $730 and $810, are incorrect as they do not align with the 1:3 ratio described in the question.

5. Which of the following values is the greatest?

• A. 2/11
• B. 5.4
• C. 13/3
• D. 6.25

Correct answer: D

Rationale: To determine the greatest value among the given options, convert the fractions to decimal form. 2/11 is approximately 0.1818, 5.4 is a decimal itself, 13/3 is approximately 4.333, and 6.25 is a decimal. Comparing these values, 6.25 is the largest among them. Therefore, option D, 6.25, is the correct answer. Choices A, B, and C are smaller values compared to 6.25, making them incorrect answers.

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