Nursing Elites

1. A person drives 300 miles at 60 mph, then another 200 miles at 80 mph, with a 30-minute break. How long does the trip take?

• A. 5.5 hours
• B. 7 hours
• C. 6 hours
• D. 4.5 hours

Correct answer: C

Rationale: To find the total time, we calculate the time taken for each segment: 300 miles at 60 mph = 300 miles ÷ 60 mph = 5 hours; 200 miles at 80 mph = 200 miles ÷ 80 mph = 2.5 hours. Adding these gives 5 hours + 2.5 hours = 7.5 hours. Converting the 30-minute break to hours (30 minutes ÷ 60 = 0.5 hours), the total time taken is 7.5 hours + 0.5 hours = 8 hours. Therefore, the correct answer is not among the given choices. The rationale provided in the original question is incorrect as it does not account for the break time and has a calculation error in adding the individual times.

2. What is the range in the number of flights the flight attendant made?

• A. 20
• B. 25
• C. 29
• D. 32

Correct answer: B

Rationale: The range is calculated as the difference between the largest and smallest values in a dataset. In this case, the largest number of flights made by the flight attendant in a month was 79, and the smallest number was 54. Therefore, the range is 79 - 54 = 25. Choices A, C, and D are incorrect as they do not reflect the correct calculation of the range based on the given data.

3. Which statement about the following set is true? {60, 5, 18, 20, 37, 37, 11, 90, 72}

• A. The median and the mean are equal.
• B. The mean is less than the mode.
• C. The mode is greater than the median.
• D. The median is less than the mean.

Correct answer: D

Rationale: To find the median, we first need to arrange the set in ascending order: {5, 11, 18, 20, 37, 37, 60, 72, 90}. The median is the middle value, which is 37 in this case. The mean is calculated by adding all numbers and dividing by the total count, which gives a mean greater than 37. Therefore, the statement that the median is less than the mean is correct. Choice A is incorrect because the median and mean are not equal in this set. Choice B is incorrect as the mean is greater than the mode in this set. Choice C is incorrect as the mode is 37, which is equal to the median, not greater.

4. In a study where 60% of respondents use smartphones to check their email, and 5,000 respondents were included, how many respondents use smartphones for email?

• A. 3,000 respondents
• B. 2,500 respondents
• C. 5,000 respondents
• D. 1,000 respondents

Correct answer: A

Rationale: In the study, 60% of 5,000 respondents using smartphones for email would equal 3,000 respondents, not the total number of respondents. Therefore, the correct answer is 3,000 respondents. Choice B, 2,500 respondents, is incorrect because it doesn't consider the percentage of smartphone users. Choice C, 5,000 respondents, is incorrect as it represents the total number of respondents, not the specific number using smartphones for email. Choice D, 1,000 respondents, is incorrect as it is not the correct calculation based on the given information.

5. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?

• A. Histogram
• B. Pie chart
• C. Bar graph
• D. Scatter plot

Correct answer: A

Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.

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