a patient requires a 30 increase in the dosage of her medication her current dosage is 270 mg what will her dosage be after the increase
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ATI TEAS 7

TEAS 7 Math Practice Test

1. A patient requires a 30% increase in the dosage of their medication. Their current dosage is 270 mg. What will their dosage be after the increase?

Correct answer: D

Rationale: To calculate the 30% increase, find 30% of 270 mg: 0.30 x 270 mg = 81 mg. Add this increase to the original dosage: 270 mg + 81 mg = 351 mg. Therefore, the patient's dosage after the 30% increase will be 351 mg. Choice A (81 mg) is incorrect as it only represents the calculated increase, not the total dosage post-increase. Choice B (270 mg) is the original dosage and does not account for the 30% increase. Choice C (300 mg) is the original dosage plus 30 mg, not the correct calculation with a 30% increase.

2. How many kiloliters are in 147 liters?

Correct answer: A

Rationale: To convert liters to kiloliters, divide by 1000 since there are 1000 liters in a kiloliter. Therefore, 147 liters = 0.147 kiloliters. Choice B is incorrect as it incorrectly moves the decimal point. Choices C and D are significantly larger than the correct answer, indicating an incorrect conversion factor used.

3. Express 18/5 as a reduced mixed number.

Correct answer: A

Rationale: 18/5 = 3 with a remainder of 3, so it is 3 3/5. 3 1/15 is equivalent to 46/15 which is greater than 18/5 3 1/18 converts to 55/18 which is also greater than 18/5 3 1/54 converts to 163/54

4. Simplify the expression. Which of the following is correct? (3/2)(8/3) ÷ (5/4)

Correct answer: B

Rationale: Using PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction): (3/2)(8/3) ÷ (5/4) = (24/6) ÷ (5/4) = (4/1) ÷ (5/4). To divide fractions, the second fraction is flipped and then multiplied by the first fraction, resulting in (4/1)(4/5) = (16/5), which simplifies to 3(1/5) or 2.

5. What is the domain for the function y = 1/x?

Correct answer: A

Rationale: The domain of a function consists of all possible input values that produce a valid output. In the case of y = 1/x, the function is undefined when x = 0 because division by zero is not defined in mathematics. Therefore, the correct domain for y = 1/x is all real numbers except 0 (Choice A). Choice B, x > 0, is incorrect because it excludes the value x = 0. Choice C, x = 0, is also incorrect as x = 0 is not a valid part of the domain due to the function being undefined at this point. Choice D, x = 1, is unrelated to the domain of the function and does not represent the set of valid input values for y = 1/x.

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