which of the following organisms would not have eukaryotic cells

HESI A2

HESI A2 Biology Practice Test

1. Which of the following organisms would not have eukaryotic cells?

A. Bacteria
B. Dog
C. Human
D. Onion

Correct answer: A

Rationale: The correct answer is A, Bacteria. Bacteria do not have eukaryotic cells. They are single-celled organisms with prokaryotic cells. Dogs, humans, and onions are all multicellular organisms that possess eukaryotic cells. Therefore, choices B, C, and D have eukaryotic cells and are not the correct answer.

2. What is the purpose of the mitochondria?

A. Control the cell
B. Create energy
C. Create proteins
D. Package waste for removal

Correct answer: B

Rationale: The correct answer is B: Create energy. The primary purpose of the mitochondria is to generate energy for the cell. Mitochondria are known as the 'powerhouses' of the cell because they produce ATP (adenosine triphosphate), which is the energy currency used by cells to carry out various functions and processes. Choice A is incorrect as the mitochondria do not control the cell but rather produce energy. Choice C is incorrect as protein synthesis primarily occurs in the ribosomes. Choice D is incorrect as packaging waste for removal is a function associated with lysosomes, not mitochondria.

3. How should a researcher test the hypothesis that a particular species of bird vocalizes most in the hours around dawn?

A. Observe a flock of the birds in captivity and record them at two-hour intervals from predawn until sunset for a month.
B. Observe a flock of the birds in the wild and record them at one-hour intervals from predawn until sunset in several seasons.
C. Observe a flock of the birds in the wild and record them in predawn and postdawn hours every day for six months.
D. Observe a flock of the birds in the wild, record them at one-hour intervals for a month, and compare that recording to recordings of other species.

Correct answer: C

Rationale: Observing a flock of the birds in the wild and recording them in predawn and postdawn hours every day for six months would be the best way to test the hypothesis that a particular species of bird vocalizes most in the hours around dawn. This method allows for consistent monitoring of the birds during specific times of interest over an extended period, providing a comprehensive dataset to accurately analyze the vocalization patterns. Options A and B do not focus specifically on dawn hours, making them less suitable for testing the hypothesis. Option D introduces a comparison with other species, which is unnecessary and distracts from the main objective of studying the vocalization pattern of the particular bird species around dawn.

4. RNA is made from DNA through a process called ___________.

A. transcription
B. synthesis
C. translation
D. replication

Correct answer: A

Rationale: RNA is made from DNA through a process called transcription. During transcription, an enzyme called RNA polymerase reads the DNA template and synthesizes a complementary RNA molecule. This process is essential for gene expression and allows the information encoded in DNA to be converted into functional RNA molecules. Choice B, 'synthesis,' is incorrect as it is a general term and does not specifically describe the process of RNA formation from DNA. Choice C, 'translation,' is incorrect as it refers to the process where the mRNA is used to assemble amino acids during protein synthesis, not the conversion of DNA to RNA. Choice D, 'replication,' is incorrect as it is the process of making an identical copy of DNA, not converting DNA into RNA.

5. Imagine that two parents both carry the recessive gene for cystic fibrosis. Any homozygous recessive offspring will manifest the disease. What percentage of the offspring is predicted to be carriers but not manifest the disease?

A. 0%
B. 25%
C. 50%
D. 100%

Correct answer: B

Rationale: When both parents carry the recessive gene for cystic fibrosis (homozygous recessive), there is a 25% chance for each offspring to inherit two recessive alleles and, therefore, manifest the disease. There is also a 50% chance for each offspring to inherit one recessive allele and one dominant allele, making them carriers of the disease but not manifest it. Therefore, 25% of the offspring are predicted to be carriers but not manifest the disease. Choice A (0%) is incorrect because there is a portion of offspring that will be carriers. Choice C (50%) is incorrect as this percentage corresponds to carriers who will not manifest the disease. Choice D (100%) is incorrect as not all offspring will be carriers and not manifest the disease.