ATI TEAS 7
ATI TEAS Science Test
1. Which of the following is NOT a function of the lymphatic system?
- A. Removing substances from the blood.
- B. Releasing hormones.
- C. Combating disease.
- D. Maintaining tissue fluid balance.
Correct answer: B
Rationale: The correct answer is B. Releasing hormones is not a function of the lymphatic system. The lymphatic system plays crucial roles in removing substances from the blood, combating disease through the production of immune cells, and maintaining tissue fluid balance by circulating lymph. Releasing hormones is primarily the function of endocrine glands, not the lymphatic system.
2. A person who carries a pathogen but does not exhibit any symptoms is considered:
- A. Asymptomatic carrier
- B. Opportunistic pathogen
- C. Nosocomial infection
- D. Vector-borne disease
Correct answer: A
Rationale: An asymptomatic carrier is a person who carries a pathogen, such as a virus or bacterium, without showing any symptoms of the infection. Despite lacking symptoms, asymptomatic carriers can still transmit the pathogen to others, potentially causing illness in those they contact. This term specifically pertains to infected individuals who do not manifest symptoms, distinguishing them from symptomatic carriers who do exhibit signs of the infection. Option A is the most fitting choice as it accurately characterizes a person carrying a pathogen without displaying symptoms. B) Opportunistic pathogen: This term describes pathogens that typically do not cause disease in healthy individuals but can be pathogenic in those with weakened immune systems. C) Nosocomial infection: This term refers to infections acquired in a hospital or healthcare facility. D) Vector-borne disease: This term relates to diseases transmitted to humans by vectors like mosquitoes or ticks.
3. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?
- A. 31.25 mL
- B. 32 mL
- C. 30 mL
- D. 31.3 mL
Correct answer: B
Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.
4. Which type of reaction typically undergoes condensation reactions?
- A. Catabolism
- B. Anabolism
- C. Exothermic
- D. Endothermic
Correct answer: B
Rationale: The correct answer is 'B: Anabolism.' Anabolic reactions typically involve condensation reactions, where smaller molecules are joined together to form larger molecules by releasing water as a byproduct. This process is fundamental in the synthesis of complex molecules such as proteins and nucleic acids. Choice A, 'Catabolism,' involves decomposition reactions where larger molecules are broken down into smaller ones, which is the opposite of condensation reactions. Choices C and D, 'Exothermic' and 'Endothermic,' refer to the heat exchange during a reaction and are not directly related to the process of condensation reactions.
5. When unpolarized light passes through a polarizing filter, the intensity of the transmitted light is:
- A. Completely absorbed
- B. Reduced by half
- C. Unaffected
- D. Doubled
Correct answer: B
Rationale: When unpolarized light passes through a polarizing filter, the filter only allows light waves oscillating in a specific direction to pass through while blocking light waves oscillating in other directions. Since unpolarized light consists of light waves oscillating in all possible directions, when it passes through a polarizing filter, only half of the light waves (those oscillating in the direction allowed by the filter) are transmitted. As a result, the intensity of the transmitted light is reduced by half. Choice A is incorrect because the light is not completely absorbed; choice C is incorrect because the polarizing filter affects the transmitted light; and choice D is incorrect because the intensity does not double, but rather decreases by half due to the selective transmission of light waves in a specific direction by the polarizing filter.
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