ATI TEAS 7
TEAS 7 Science Practice Test
1. What describes a cell’s reaction to being placed in a hypertonic solution?
- A. The cell will shrink as water is pulled out of the cell to equalize the concentrations inside and outside of the cell.
- B. The cell will swell as water is pulled into the cell to equalize the concentrations inside and outside of the cell.
- C. The cell will remain the same size since the concentrations inside and outside the cell are equal to begin with.
- D. The pH inside the cell will drop in order to equalize the pH inside and outside the cell.
Correct answer: A
Rationale: A cell placed in a hypertonic solution has a higher solute concentration outside the cell compared to inside. This creates a concentration gradient that causes water to move out of the cell through osmosis to equalize the concentrations on both sides. As a result, the cell will shrink or undergo plasmolysis, as water is pulled out of the cell. Choice B is incorrect because a hypertonic solution causes water to move out of the cell, leading to shrinkage rather than swelling. Choice C is incorrect as a hypertonic solution results in a concentration gradient that leads to water leaving the cell, causing it to shrink. Choice D is incorrect because pH is not directly affected by being placed in a hypertonic solution; the change in solute concentration primarily impacts water movement.
2. What is the term for the shedding of the outermost layer of the epidermis?
- A. Desquamation
- B. Exfoliation
- C. Keratinization
- D. Epidermolysis
Correct answer: A
Rationale: Desquamation is the correct term for the shedding of the outermost layer of the epidermis. This process is essential for skin renewal, allowing the removal of dead skin cells from the skin's surface. Exfoliation, on the other hand, involves the removal of dead skin cells through mechanical or chemical methods. Keratinization refers to the process where skin cells produce the protein keratin, contributing to the skin's protective barrier. Epidermolysis is a condition characterized by the separation of the epidermis from the dermis due to a structural defect in the skin.
3. Which of the following types of stem cells can differentiate into any cell type, including forming an entire organism?
- A. Totipotent stem cells
- B. Multipotent stem cells
- C. Pluripotent stem cells
- D. Hematopoietic stem cells
Correct answer: A
Rationale: Totipotent stem cells possess the unique ability to differentiate into any cell type, including forming an entire organism. These cells have the highest potency level and can give rise to both embryonic and extraembryonic cell types, allowing them to develop into a complete organism. Multipotent stem cells (Choice B) can differentiate into a limited range of cell types within a specific tissue or organ. Pluripotent stem cells (Choice C) can differentiate into any cell type in the body except for those needed to support and develop a fetus. Hematopoietic stem cells (Choice D) are a type of multipotent stem cell that can differentiate into various blood cell types.
4. Which of the following suffixes has an action that means 'relating to'?
- A. -ic
- B. -ology
- C. -ation
- D. -ate
Correct answer: A
Rationale: The correct answer is '-ic.' The suffix '-ic' means 'relating to,' as seen in words like 'artistic' (relating to art). - 'B' is incorrect as the suffix '-ology' refers to the study of a subject, not 'relating to.' - 'C' is incorrect as the suffix '-ation' is used to form nouns expressing an action or process, not 'relating to.' - 'D' is incorrect as the suffix '-ate' is used to form verbs or nouns denoting an office, function, or rank, not 'relating to.'
5. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?
- A. 31.25 mL
- B. 32 mL
- C. 30 mL
- D. 31.3 mL
Correct answer: B
Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.
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