ATI TEAS 7
ATI TEAS 7 science review
1. Which type of cartilage allows for smooth movement at joints and absorbs shock?
- A. Hyaline cartilage
- B. Fibrocartilage
- C. Elastic cartilage
- D. None of the above
Correct answer: B
Rationale: Fibrocartilage is the correct answer. It is found in areas requiring both support and resilience, such as the intervertebral discs and knee joints. Fibrocartilage contains collagen fibers for strength and proteoglycans for resilience, making it suitable for functions that involve smooth movement at joints and shock absorption. Hyaline cartilage, while providing structural support, is not primarily responsible for smooth movement and shock absorption. Elastic cartilage is more flexible and is found in locations like the ear and epiglottis, but it is not known for its shock-absorbing properties. Choosing 'None of the above' disregards the correct option of fibrocartilage, which is specifically designed for the functions described in the question.
2. When a biologist describes the physical and visible expression of a genetic trait, which of the following is being referred to?
- A. Phenotype
- B. Allele
- C. Gamete
- D. Genotype
Correct answer: A
Rationale: The correct answer is A: Phenotype. Phenotype specifically refers to the observable physical characteristics resulting from the interaction of an individual's genetic makeup (genotype) with environmental influences. It represents the outward expression of an organism's genetic makeup. Allele, represented by choice B, refers to different forms of a gene and is not the visible expression of a trait. Gamete, represented by choice C, is a reproductive cell and not directly related to the physical expression of traits. Genotype, represented by choice D, refers to the genetic makeup of an organism and is distinct from the observable physical characteristics denoted by phenotype.
3. What is the difference between a germline mutation and a somatic mutation?
- A. Germline mutations are passed to offspring, while somatic mutations are not.
- B. Germline mutations occur in reproductive cells, while somatic mutations occur in body cells.
- C. Germline mutations only affect genes, while somatic mutations can affect any DNA.
- D. Germline mutations are always beneficial, while somatic mutations are always harmful.
Correct answer: B
Rationale: Rationale: - Germline mutations are changes in the DNA of reproductive cells (sperm or egg cells) and can be passed on to offspring, affecting all cells in the resulting organism. - Somatic mutations are changes in the DNA of non-reproductive cells (body cells) and are not passed on to offspring. These mutations only affect the cells that arise from the mutated cell. - Option A is incorrect because somatic mutations are not passed to offspring. - Option C is incorrect because both germline and somatic mutations can affect any DNA. - Option D is incorrect because the effects of mutations, whether germline or somatic, can be beneficial, harmful, or have no significant impact.
4. The Hardy-Weinberg equilibrium describes a population that is:
- A. Undergoing rapid evolution due to strong directional selection.
- B. Not evolving and at genetic equilibrium with stable allele frequencies.
- C. Experiencing a founder effect leading to a reduction in genetic diversity.
- D. Dominated by a single homozygous genotype that eliminates all variation.
Correct answer: B
Rationale: The Hardy-Weinberg equilibrium describes a theoretical population in which allele frequencies remain constant from generation to generation, indicating that the population is not evolving. This equilibrium occurs under specific conditions: no mutation, no gene flow, random mating, a large population size, and no natural selection. In this scenario, all genotypes are in proportion to the allele frequencies, and genetic diversity is maintained. Options A, C, and D do not accurately describe a population in Hardy-Weinberg equilibrium. Option A suggests rapid evolution due to strong directional selection, which would disrupt the equilibrium. Option C mentions a founder effect, which can reduce genetic diversity but is not a characteristic of a population in Hardy-Weinberg equilibrium. Option D describes a population dominated by a single homozygous genotype, which also does not align with the genetic diversity seen in a population at Hardy-Weinberg equilibrium.
5. How do spindle fiber dynamics and microtubule attachment regulate cell cycle checkpoints?
- A. Misaligned chromosomes fail to attach to microtubules, triggering a delay in anaphase onset.
- B. The presence of unattached kinetochores on the centromeres sends a signal to pause cell cycle progression.
- C. Microtubule instability and rapid depolymerization lead to the activation of checkpoint proteins.
- D. All of the above.
Correct answer: D
Rationale: A) Misaligned chromosomes fail to attach to microtubules, triggering a delay in anaphase onset: Proper attachment of chromosomes to spindle fibers is essential for accurate segregation of genetic material during cell division. Misaligned chromosomes that fail to attach to microtubules can lead to delays in anaphase onset, allowing the cell to correct errors before proceeding with division. B) The presence of unattached kinetochores on the centromeres sends a signal to pause cell cycle progression: Kinetochores at the centromeres help attach chromosomes to spindle fibers. When kinetochores are unattached or improperly attached to microtubules, they signal the cell to pause cell cycle progression, ensuring proper chromosome alignment before division. C) Microtubule instability and rapid depolymerization lead to the activation of checkpoint proteins: While microtubule dynamics are crucial for cell division, microtubule instability and rapid depolymerization can disrupt chromosome attachment. However, this mechanism is not directly related to the activation of cell cycle checkpoint proteins, making this statement incorrect. Therefore, choices A and B accurately describe how spindle fiber dynamics and microtubule attachment regulate cell cycle checkpoints, making option D the correct answer.
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