Nursing Elites

1. What term describes the bending of waves around obstacles or through openings?

• A. Reflection
• B. Refraction
• C. Diffraction
• D. Absorption

Correct answer: C

Rationale: The correct answer is C, Diffraction. Diffraction is the phenomenon that explains the bending of waves around obstacles or through openings. When waves encounter obstacles or pass through openings, they spread out and bend around them. Reflection (Choice A) involves waves bouncing back when they encounter a surface without bending, refraction (Choice B) is the bending of waves when passing from one medium to another due to a change in speed, and absorption (Choice D) is the process of a wave being taken in by a material rather than bending or bouncing.

2. What are the three regions of the small intestine?

• A. Duodenum, ileum, jejunum
• B. Cecum, ileum, jejunum
• C. Duodenum, jejunum, ileum
• D. Duodenum, jejunum, colon

Correct answer: C

Rationale: The correct answer is C: Duodenum, jejunum, ileum. The small intestine is divided into three regions: the duodenum, jejunum, and ileum. The duodenum is the initial segment where most chemical digestion takes place. The jejunum and ileum follow the duodenum and are primarily responsible for nutrient absorption. Choice A is incorrect because the order is incorrect. Choice B is incorrect because the cecum is part of the large intestine, not the small intestine. Choice D is incorrect because the colon is part of the large intestine, not the small intestine.

3. What is the difference between alpha decay and beta decay?

• A. Both release the same type of particle.
• B. Alpha decay releases a helium nucleus, while beta decay releases an electron or positron.
• C. Alpha decay is more common than beta decay.
• D. They both convert one element into another, but in different ways.

Correct answer: B

Rationale: The correct answer is B. Alpha decay involves the release of a helium nucleus, which consists of two protons and two neutrons. In contrast, beta decay releases an electron (beta-minus decay) or a positron (beta-plus decay). This significant distinction in the particles emitted during the decay processes distinguishes alpha decay from beta decay. Choice A is incorrect because alpha and beta decay release different types of particles. Choice C is incorrect as beta decay is more common than alpha decay in many cases. Choice D is incorrect as it does not specifically address the particles released during alpha and beta decay.

4. Where is oxygen exchanged between blood and tissues?

• A. capillaries
• B. veins
• C. ventricles
• D. arteries

Correct answer: A

Rationale: Oxygen is exchanged between blood and tissues primarily at the capillaries. Capillaries are the smallest blood vessels where the exchange of oxygen, nutrients, and waste products occurs between the blood and the tissues. This exchange process is crucial for delivering oxygen to the body's cells and eliminating carbon dioxide waste. Veins carry blood back to the heart, arteries carry blood away from the heart, and ventricles are the lower chambers of the heart responsible for pumping blood. Therefore, capillaries are the correct answer for where oxygen is exchanged between blood and tissues.

5. How does polarization affect the intensity of light passing through a polarizing filter?

• A. All light passes through regardless of polarization.
• B. Light with the same polarization as the filter passes through, while others are blocked.
• C. Light with higher intensity passes through, while weaker light is blocked.
• D. The intensity is reduced for all light, regardless of polarization.

Correct answer: B

Rationale: A polarizing filter only allows light waves with a specific orientation (polarization) to pass through while blocking light waves with different orientations. Therefore, light with the same polarization as the filter will pass through, while light with different polarizations will be blocked. This results in a reduction in intensity for light passing through the polarizing filter. Choice A is incorrect because a polarizing filter selectively filters light based on its polarization. Choice C is incorrect as the intensity of light passing through is determined by its polarization, not solely its intensity. Choice D is incorrect because a polarizing filter affects light based on its polarization, not uniformly reducing the intensity for all light passing through.

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