talk to me about how to tell apart these three types of graphsscatterplots quadratic exponential linear
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ATI TEAS 7

Math Practice TEAS Test

1. How can you distinguish between these three types of graphs - scatterplots: Quadratic, Exponential, Linear?

Correct answer: A

Rationale: To differentiate between the three types of graphs - scatterplots, a linear graph will display a straight line, a quadratic graph will have a U-shape, and an exponential graph will show a rapid rise or fall in one direction. Choice B is incorrect because linear graphs are represented by straight lines, not curved lines. Choice C is incorrect as linear graphs do not exhibit zigzag patterns, and exponential graphs do not typically result in flat lines. Choice D is incorrect because quadratic graphs form a U-shape, not a W-shape, and exponential graphs do not represent vertical lines.

2. How do you find the least common multiple?

Correct answer: A

Rationale: The correct way to find the least common multiple is to list all the multiples of each number and then identify the smallest common multiple. Choice A is correct because it describes the correct process. Listing factors, as suggested in choice B, helps in finding the greatest common factor, not the least common multiple. Dividing the largest number by the smallest, as mentioned in choice C, does not help find the least common multiple. Multiplying the two numbers together, as stated in choice D, results in their least common multiple when the numbers have no common factors.

3. What is the value of 0.0523 expressed as a fraction?

Correct answer: A

Rationale: To convert a decimal to a fraction, place the decimal value over the place value of the last digit. In this case, 0.0523 can be expressed as 523/10000 since the last digit is in the ten-thousandths place. Choice A is correct. Choices B, C, and D are incorrect because they represent different decimal values and do not match the correct conversion of 0.0523.

4. While at the local ice skating rink, Cora went around the rink 27 times in total. She slipped and fell 20 of the 27 times she skated around the rink. What approximate percentage of the times around the rink did Cora not slip and fall?

Correct answer: C

Rationale: To find the approximate percentage of the times Cora did not slip and fall, subtract the times she fell (20) from the total times around the rink (27), which gives 7. Then, divide the number of times she did not slip and fall (7) by the total times around the rink (27) and multiply by 100 to get the percentage. So, 7 divided by 27 equals 0.259, which rounds to approximately 26%. Therefore, the correct answer is 26%. Choice A (37%) is incorrect because it does not reflect the calculation based on the given information. Choice B (74%) is incorrect as it is not the result of the correct calculation. Choice D (15%) is incorrect as it does not match the calculated percentage based on the scenario provided.

5. Simplify the following expression: 4 * (2/3) ÷ 1 * (1/6)

Correct answer: C

Rationale: To simplify the expression, first convert the mixed numbers into fractions: 4 * (2/3) ÷ 1 * (1/6). This becomes 4 * 2/3 ÷ 1 * 1/6. Next, perform the multiplication and division from left to right: 8/3 ÷ 1 * 1/6 = 8/3 * 1 * 6 = 8/3 * 6 = 16. Therefore, the correct answer is 4. Choice A (2) is incorrect as it does not represent the final simplified expression. Choice B (3 1/3) is incorrect as it does not match the result of simplifying the expression. Choice D (4 1/2) is incorrect as it does not match the result of simplifying the expression.

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