ATI TEAS 7
ATI TEAS Math Practice Test
1. Solve for y: 2y + 5 = 25 * 10
- A. y = 25
- B. y = 100
- C. y = 150
- D. y = 200
Correct answer: B
Rationale: To solve the equation 2y + 5 = 25 * 10, start by simplifying the right side: 25 * 10 = 250. Then, subtract 5 from both sides to isolate 2y: 2y = 250 - 5 = 245. Finally, divide by 2 to find the value of y: y = 245 / 2 = 122.5. Therefore, the correct answer is y = 122.5. Choices A, C, and D are incorrect as they do not result from the correct calculation steps.
2. Veronica is making a holiday schedule. 35% of staff members will be on vacation, and 20% of the remainder are certified to work. What percentage of the staff is certified and available?
- A. 0.07
- B. 0.13
- C. 0.65
- D. 0.8
Correct answer: A
Rationale: To find the percentage of staff certified and available, we first calculate the percentage of staff members not on vacation, which is 100% - 35% = 65%. Then, 20% of this group is certified to work, which is 20% of 65% = 0.20 * 65% = 13%. Therefore, Veronica has 13% of the staff certified and available to work. The correct answer is 0.13 (or 13%). Choice C (0.65) is incorrect because it represents the percentage of staff members not on vacation, not the percentage that is certified and available. Choice D (0.8) is incorrect as it is not the correct percentage of staff members certified and available. Choice B (0.13) is the correct answer, not choice A (0.07), as 0.07 represents 7%, not 13%.
3. Which of the following values is the greatest?
- A. 2/11
- B. 5.4
- C. 13/3
- D. 6.25
Correct answer: D
Rationale: To determine the greatest value among the given options, convert the fractions to decimal form. 2/11 is approximately 0.1818, 5.4 is a decimal itself, 13/3 is approximately 4.333, and 6.25 is a decimal. Comparing these values, 6.25 is the largest among them. Therefore, option D, 6.25, is the correct answer. Choices A, B, and C are smaller values compared to 6.25, making them incorrect answers.
4. If Stella's current weight is 56 kilograms, what is her approximate weight in pounds?
- A. 123 pounds
- B. 110 pounds
- C. 156 pounds
- D. 137 pounds
Correct answer: A
Rationale: To convert kilograms to pounds, you multiply the weight in kilograms by 2.2. So, 56 kilograms * 2.2 = 123.2 pounds, which can be approximated to 123 pounds. Therefore, Choice A is correct. Choices B, C, and D are incorrect as they do not match the correct conversion from kilograms to pounds for Stella's weight of 56 kilograms.
5. How many whole boxes measuring 2 ft * 2 ft * 2 ft can be stored in a room measuring 9 ft * 9 ft * 9 ft, without altering the box size?
- A. 125
- B. 64
- C. 18
- D. 92
Correct answer: D
Rationale: The total volume of the room is 729 ft³ (9 ft * 9 ft * 9 ft). Each box has a volume of 8 ft³ (2 ft * 2 ft * 2 ft). Dividing the room's volume by the box volume, we get 729 ft³ / 8 ft³ ≈ 91.125. Since we can't have a fraction of a box, the maximum number of whole boxes that can fit is 92. Therefore, the correct answer is 92. Choice A (125) is incorrect as it does not result from the correct calculation. Choice B (64) and Choice C (18) are also incorrect and do not accurately represent the number of boxes that can fit in the room based on the given dimensions.
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