Nursing Elites

1. During week 1, Nurse Cameron works 5 shifts. During week 2, she worked twice as many shifts as she did in week 1. In week 3, she added 4 shifts to the number of shifts worked in week 2. Which equation describes the number of shifts Nurse Cameron worked in week 3?

• A. Shifts = (2)(5) + 4
• B. Shifts = (4)(5) + 2
• C. Shifts = 5 + 2 + 4
• D. Shifts = (5)(2)(4)

Correct answer: A

Rationale: During week 1, Nurse Cameron worked 5 shifts. In week 2, she worked twice as many shifts as in week 1, which is 10 shifts. In week 3, she added 4 shifts to the number of shifts worked in week 2. Therefore, the total shifts in week 3 can be calculated as (2)(5) + 4 = 10 + 4 = 14 shifts. Choice A correctly represents this calculation. Choices B, C, and D are incorrect because they do not accurately reflect the given scenario and the steps needed to find the total shifts in week 3.

2. A patient requires a 30% increase in the dosage of their medication. Their current dosage is 270 mg. What will their dosage be after the increase?

• A. 81 mg
• B. 270 mg
• C. 300 mg
• D. 351 mg

Correct answer: D

Rationale: To calculate a 30% increase from the current dosage of 270 mg, first find 30% of 270, which is 81 mg. Add this 81 mg increase to the original dosage of 270 mg to get the new dosage, which is 351 mg (270 mg + 81 mg = 351 mg). Therefore, the correct answer is 351 mg. Choice A (81 mg) is incorrect because this value represents only the calculated 30% increase, not the total dosage after the increase. Choice B (270 mg) is the original dosage and does not account for the 30% increase. Choice C (300 mg) is close to the correct answer but does not consider the precise 30% increase calculation, leading to an incorrect total dosage.

3. What percentage of the total rainfall in this timeframe occurs during October?

• A. 0.135
• B. 0.151
• C. 0.169
• D. 0.177

Correct answer: B

Rationale: To calculate the percentage of rainfall that occurs during October, divide October's rainfall (4.5 inches) by the total rainfall (29.38 inches) and multiply by 100. So, (4.5 / 29.38) * 100 = 15.31%. Among the choices given, option B, 0.151, is the closest to this calculated percentage. Options A, C, and D are not correct as they do not match the accurate calculation based on the provided data.

4. How many milligrams are in 5 grams?

• A. 0.005 mg
• B. 50 mg
• C. 500 mg
• D. 5000 mg

Correct answer: D

Rationale: To convert grams to milligrams, you need to multiply by 1000 since 1 gram is equal to 1000 milligrams. Therefore, 5 grams is equal to 5 * 1000 = 5000 milligrams. Choices A, B, and C are incorrect because they do not correctly convert grams to milligrams. Choice A is incorrect as it represents a decrease in value instead of an increase when converting from grams to milligrams. Choice B is incorrect because it is a factor of 10 lower than the correct answer. Choice C is incorrect as it is a factor of 10 lower than the correct answer. Thus, the correct answer is D, 5000 mg.

5. What is the least common multiple? What is the least common factor?

• A. The smallest number that both numbers multiply into; the smallest number that divides evenly into both
• B. The largest number that both numbers multiply into; the smallest number that divides evenly into both
• C. The smallest number that both numbers divide into evenly; the smallest number that multiplies into both
• D. The smallest number that both numbers divide into evenly; the smallest number that both multiply into

Correct answer: A

Rationale: The least common multiple is the smallest number that both numbers multiply into, which means it is the smallest number that both numbers can be evenly divided by without leaving a remainder. The least common factor, on the other hand, is the smallest number that divides both numbers without leaving a remainder. Therefore, choice A is correct as it accurately defines the least common multiple and factor. Choices B, C, and D are incorrect because they provide inaccurate definitions or mix up the concepts of multiplication and division in relation to finding the least common multiple and factor.

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