jessica buys 10 cans of paint red paint costs 1 per can and blue paint costs 2 per can in total she spends 16 how many red cans did she buy
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ATI TEAS 7

TEAS Math Practice Test

1. Jessica buys 10 cans of paint. Red paint costs $1 per can, and blue paint costs $2 per can. In total, she spends $16. How many red cans did she buy?

Correct answer: C

Rationale: Let r be the number of red cans and b be the number of blue cans. The total cans equation is r + b = 10. The total cost equation is r + 2b = 16. By solving these equations simultaneously, we find r = 4. Therefore, Jessica bought 4 red cans. Choice A, 2 red cans, is incorrect because it does not satisfy the total cans or total cost condition. Choices B and D are also incorrect as they do not fulfill both conditions simultaneously.

2. A gift box has a length of 14 inches, a height of 8 inches, and a width of 6 inches. How many square inches of wrapping paper are needed to wrap the box?

Correct answer: C

Rationale: To find the surface area of a rectangular prism, you use the formula SA = 2lw + 2wh + 2hl, where l is the length, w is the width, and h is the height. Substituting the given dimensions, the calculation would be SA = 2(14)(6) + 2(6)(8) + 2(8)(14) = 168 + 96 + 224 = 488 square inches. Therefore, 488 square inches of wrapping paper are needed to wrap the box. Choice A (56), Choice B (244), and Choice D (672) are incorrect because they do not represent the correct surface area calculation for the given box dimensions.

3. Sarah buys one red can of paint every month. If she continues this for four months, how many red cans did she buy?

Correct answer: C

Rationale: The correct answer is C. Sarah buys one red can of paint every month for four months. Therefore, if she continues this pattern for four months, she would have bought a total of 4 red cans. Choices A, B, and D are incorrect because they do not reflect the total number of red cans accumulated over the specified period of four months.

4. Solve the following equation: 3(2y+50)โˆ’4y=500

Correct answer: B

Rationale: To solve the equation 3(2y+50)โˆ’4y=500, first distribute to get 6y+150โˆ’4y=500. Combining like terms results in 2๐‘ฆ + 150 = 500. By subtracting 150 from both sides, we get 2y = 350. Dividing by 2 gives y = 175. Therefore, the correct answer is B. Choices A, C, and D are incorrect because they do not correctly follow the steps of distributing, combining like terms, and isolating the variable to solve for y.

5. Solve for x: x + 5 = x - 3.

Correct answer: A

Rationale: To solve the equation x + 5 = x - 3, we aim to isolate x. By subtracting x from both sides, we get 5 = -3, which is not possible. This indicates that the equation has no solution. Therefore, the correct answer is x = -5. Choices B, C, and D are incorrect as they do not yield a valid solution when substituted back into the original equation.

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