in testing how quickly a rat dies by the amount of poison it eats which of the following is the independent variable and which is the dependent variab
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ATI TEAS 7

ATI TEAS Science

1. When testing how quickly a rat dies based on the amount of poison it eats, which of the following is the independent variable and which is the dependent variable?

Correct answer: B

Rationale: The correct answer is B. In this experiment, the independent variable is the amount of poison because it is what is being manipulated by the researcher. The dependent variable is how quickly the rat dies, as it is the outcome that is being measured based on the different amounts of poison administered. Choice A is incorrect because the independent variable should be what is being manipulated or changed, which is the amount of poison in this case. Choice C is incorrect because whether the rat eats the poison is not being varied or controlled by the researcher. Choice D is incorrect because the cage the rat is kept in is not relevant to the relationship being studied between the amount of poison and the rat's survival time.

2. How does AIDS impair the immune system?

Correct answer: A

Rationale: AIDS targets and destroys Helper T-Cells, which play a crucial role in coordinating the immune response. By affecting these cells, AIDS prevents the activation of other important immune cells like Cytotoxic T-Cells or B-Cells. This disruption in the immune system's communication and response mechanisms leads to immune system failure and increased vulnerability to infections. Choices B and C are incorrect because they refer to the role of IgE in allergic reactions, which is not directly related to how AIDS impairs the immune system. Choice D is also incorrect as Helper T-Cells being destroyed in AIDS is not about deceiving the body into attacking itself, but rather the direct impact on immune system function.

3. Which blood vessels are responsible for carrying oxygenated blood away from the heart to the rest of the body?

Correct answer: B

Rationale: Arteries are the blood vessels responsible for carrying oxygenated blood away from the heart to the rest of the body. Their thick, muscular walls allow them to withstand high pressure and efficiently transport blood to various tissues and organs throughout the body. Veins (choice A) carry deoxygenated blood back to the heart, capillaries (choice C) facilitate the exchange of nutrients and waste products between the blood and tissues, and venules (choice D) are small blood vessels that collect blood from the capillaries and gradually converge into veins.

4. What is the difference between a ventral and dorsal root of a spinal nerve?

Correct answer: A

Rationale: The correct answer is A: Ventral carries motor, dorsal carries sensory information. In the spinal nerve, the ventral root carries motor information from the spinal cord to the muscles, while the dorsal root carries sensory information from the peripheral sensory receptors to the spinal cord. Therefore, other choices are incorrect. Choice B is incorrect as it states the opposite roles of ventral and dorsal roots. Choice C is incorrect as the size comparison between ventral and dorsal roots is not related to their functions. Choice D is incorrect as the terms 'anteriorly' and 'posteriorly' are not commonly used to describe the locations of ventral and dorsal roots in relation to each other.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

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