Nursing Elites

1. If a tree grows an average of 4.2 inches in a day, what is the rate of change in its height per month? Assume a month is 30 days.

• A. 0.14 inches per month
• B. 4.2 inches per month
• C. 34.2 inches per month
• D. 126 inches per month

Correct answer: D

Rationale: The tree grows at an average rate of 4.2 inches per day. To find the rate of change per month, multiply the daily growth rate by the number of days in a month (30 days): 4.2 inches/day × 30 days = 126 inches per month. Therefore, the rate of change in the tree's height is 126 inches per month, making option D the correct answer. Option A is incorrect because it miscalculates the rate based on daily growth. Option B is incorrect as it doesn't account for the total days in a month. Option C is incorrect as it overestimates the monthly growth rate.

2. Given the histograms shown below, which of the following statements is true?

• A. Group A is negatively skewed and has a mean less than Group B.
• B. Group A is positively skewed and has a mean greater than Group B.
• C. Group B is negatively skewed and has a mean greater than Group A.
• D. Group B is positively skewed and has a mean less than Group A.

Correct answer: C

Rationale: The correct answer is C. Group B is negatively skewed, indicating more high scores, leading to a higher mean for Group B when compared to Group A. Choice A is incorrect because Group A is not negatively skewed and doesn't have a mean less than Group B. Choice B is incorrect as Group A is not positively skewed and its mean is not greater than Group B. Choice D is also incorrect because Group B having a mean less than Group A contradicts the fact that Group B has a higher mean due to being negatively skewed.

3. A closet is filled with red, blue, and green shirts. If 1/4 of the shirts are green and 1/3 are red, what fraction of the shirts are blue?

• A. 1/2
• B. 1/3
• C. 5/12
• D. 1/4

Correct answer: C

Rationale: Let the total number of shirts be x. Given that 1/4 of the shirts are green and 1/3 are red, we have Green = x/4 and Red = x/3. To find the fraction of blue shirts, we subtract the fractions of green and red shirts from 1: Blue fraction = 1 - (1/4 + 1/3) = 1 - (3/12 + 4/12) = 1 - 7/12 = 5/12. Therefore, the fraction of blue shirts is 5/12. Choices A, B, and D are incorrect because they do not accurately represent the fraction of blue shirts given the information provided.

4. Which statement about the following set is true? {60, 5, 18, 20, 37, 37, 11, 90, 72}

• A. The median and the mean are equal.
• B. The mean is less than the mode.
• C. The mode is greater than the median.
• D. The median is less than the mean.

Correct answer: D

Rationale: To find the median, we first need to arrange the set in ascending order: {5, 11, 18, 20, 37, 37, 60, 72, 90}. The median is the middle value, which is 37 in this case. The mean is calculated by adding all numbers and dividing by the total count, which gives a mean greater than 37. Therefore, the statement that the median is less than the mean is correct. Choice A is incorrect because the median and mean are not equal in this set. Choice B is incorrect as the mean is greater than the mode in this set. Choice C is incorrect as the mode is 37, which is equal to the median, not greater.

5. Tom needs to buy ink cartridges and printer paper. Each ink cartridge costs $30. Each ream of paper costs $5. He has $100 to spend. Which of the following inequalities may be used to find the combinations of ink cartridges and printer paper he may purchase?

• A. 30c + 5p ≤ 100
• B. 30c + 5p = 100
• C. 30c + 5p > 100
• D. 30c + 5p < 100

Correct answer: A

Rationale: The correct inequality is 30c + 5p ≤ 100. This represents the combinations of ink cartridges (c) and printer paper (p) that Tom may purchase, ensuring the total cost is less than or equal to $100. Choice B is incorrect because the total cost should be less than or equal to $100, not equal to. Choices C and D are also incorrect as they indicate the total cost being greater than $100, which is not the case given Tom's budget limit.

Similar Questions