autoimmune diseases occur when the immune system mistakenly attacks healthy body tissues what is a potential cause of autoimmune diseases
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ATI TEAS 7

Mometrix TEAS 7 science practice test

1. Autoimmune diseases occur when the immune system mistakenly attacks healthy body tissues. What is a potential cause of autoimmune diseases?

Correct answer: C

Rationale: Autoimmune diseases result from a breakdown in immune cell self-tolerance mechanisms, leading to the immune system mistakenly attacking healthy body tissues. While deficiencies in essential vitamins and minerals or exposure to environmental toxins can impact overall health, they are not direct causes of autoimmune diseases. Deficiency in essential vitamins and minerals may weaken the immune system, making it more susceptible to various health issues but does not directly cause autoimmune diseases. Exposure to environmental toxins can trigger immune responses, but autoimmune diseases specifically stem from the breakdown of self-tolerance mechanisms within immune cells. Therefore, the correct answer is a breakdown in immune cell self-tolerance mechanisms.

2. What is the molarity of a solution made by dissolving 4.0 grams of NaCl into enough water to make 120 mL of solution? The atomic mass of Na is 23.0 g/mol, and Cl is 35.5 g/mol.

Correct answer: B

Rationale: To find the molarity, first calculate the moles of NaCl. Moles of NaCl = 4.0 g / (23.0 g/mol + 35.5 g/mol) = 0.068 mol. Next, use the formula for molarity: Molarity = moles of solute / liters of solution. Molarity = 0.068 mol / 0.120 L = 0.57 M. Therefore, the molarity of the solution is 0.57 M. Choice A, 0.34 M, is incorrect as it does not match the calculated molarity. Choice C, 0.034 M, is incorrect as it is a decimal point off from the correct molarity. Choice D, 0.057 M, is incorrect as it does not match the calculated molarity of 0.57 M.

3. During the process of oogenesis, primary oocytes produce:

Correct answer: B

Rationale: During the process of oogenesis, primary oocytes undergo meiosis to develop into secondary oocytes, which are the matured eggs released during ovulation for potential fertilization. Therefore, primary oocytes produce eggs, not sperm, oogonia, or stem cells, during oogenesis. Choice A (sperm) is incorrect as sperm is produced through spermatogenesis in males. Choice C (oogonia) is incorrect as oogonia are the cells that give rise to primary oocytes but are not the direct product of primary oocytes. Choice D (stem cells) is incorrect as primary oocytes do not directly produce stem cells during oogenesis.

4. What is the unit of measurement for force in the International System of Units (SI)?

Correct answer: A

Rationale: The unit of measurement for force in the International System of Units (SI) is the Newton (N). One Newton is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared. Therefore, the correct answer is Newton (N). The other choices are incorrect because: B) Kilogram (kg) is a unit of mass, not force; C) Joule (J) is a unit of energy; D) Meter per second squared (m/s²) is a unit of acceleration, not force.

5. How does the stability of an atom's nucleus influence its radioactive decay?

Correct answer: B

Rationale: Unstable nuclei are more likely to decay through various processes. The stability of an atom's nucleus is a crucial factor in determining whether it will undergo radioactive decay. Unstable nuclei have an excess of either protons or neutrons, causing an imbalance in the nucleus. To achieve a more stable configuration, these nuclei will undergo radioactive decay by emitting particles or energy. On the contrary, stable nuclei are less likely to undergo radioactive decay as they possess a balanced number of protons and neutrons. Choice A is incorrect because stable nuclei can still undergo radioactive decay, albeit less frequently. Choice C is incorrect as decay does not make stable nuclei more prone to it; rather, it stabilizes them. Choice D is incorrect because an element's decay rate is primarily determined by the nucleus's stability, not its position on the periodic table.

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