Nursing Elites

1. Which is larger, feet or meters? What is the correct conversion factor between feet and meters?

• A. Feet are larger; 1 foot is 0.3048 meters
• B. Meters are larger; 1 meter is 3.28 feet
• C. Feet are smaller; 1 foot is 0.5 meters
• D. Meters are smaller; 1 meter is 2 feet

Correct answer: A

Rationale: The correct answer is A. Feet are larger than meters. The conversion factor between feet and meters is 1 foot = 0.3048 meters. Choice B is incorrect as it states that meters are larger than feet, which is the opposite of the truth. Choice C is incorrect as it provides an incorrect conversion factor of 1 foot = 0.5 meters, which is inaccurate. Choice D is also incorrect as it suggests that meters are smaller than feet, which is not true.

2. Veronica has to create the holiday schedule for the neonatal unit at her hospital. 35% of her staff will be unavailable during the holidays, and of the remaining staff, only 20% are certified to work in the neonatal unit. What percentage of the total staff is certified and available to work?

• A. 7%
• B. 13%
• C. 65%
• D. 80%

Correct answer: B

Rationale: The correct answer is 13%. To find the percentage of the total staff that is certified and available to work, we first calculate the percentage of staff available, which is 100% - 35% = 65%. Then, we find the percentage of the available staff that is certified, which is 20% of 65% = 0.20 × 0.65 = 0.13, or 13%.

3. Given a double bar graph, which statement is true about the distributions of Group A and Group B?

• A. Group A is negatively skewed, Group B is normal.
• B. Group A is positively skewed, Group B is normal.
• C. Group A is positively skewed, Group B is neutral.
• D. Group A is normal, Group B is negatively skewed.

Correct answer: B

Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.

4. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at 80 mph, how long will it have been since he began the trip?

• A. 0.96 hours
• B. 6.44 hours
• C. 6.69 hours
• D. 6.97 hours

Correct answer: C

Rationale: To calculate the total time, first find the time for the first leg of the trip: 305 miles / 65 mph = 4.69 hours. Then, add the time for the second leg: 162 miles / 80 mph = 2.025 hours. Next, add the 15-minute stop in hours (15 minutes = 0.25 hours). Finally, add the times together: 4.69 hours + 2.025 hours + 0.25 hours = 6.965 hours, which rounds to 6.69 hours. Therefore, the correct answer is 6.69 hours. Choice A is incorrect because it does not account for the total driving time correctly. Choice B is incorrect as it does not include the time for the gas station stop. Choice D is wrong as it miscalculates the total time taken for the trip.

5. What is the equation that describes the relationship between x and y in the table below: x = 2, y = 6; x = 3, y = 9; x = 4, y = 12?

• A. y = 3x
• B. x = 3y
• C. y = x/3
• D. y = x + 3

Correct answer: A

Rationale: The correct answer is y = 3x. By examining the table provided, we can see that for each increase of 1 in x, y increases by 3. This consistent pattern indicates that y is three times the value of x, leading to the equation y = 3x. Choices B, C, and D do not match the pattern observed in the table and are therefore incorrect.

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