a student was asked to count birds in a given location over a 24 hour period which count would make her data most valid
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Nursing Elites

HESI A2

HESI A2 Biology 2024

1. A student was asked to count birds in a given location over a 24-hour period. Which count would make their data most valid?

Correct answer: C

Rationale: Counting birds at one feeder at consistent time intervals (noon and 6:00 P.M.) over a 24-hour period ensures that the data collected are evenly distributed and provide a more accurate representation of the bird population in that location throughout the day. This method allows for observations during different times of the day, capturing potential variations in bird activity and distribution. Choice A is not as effective as it lacks observations at different times of the day, potentially missing variations in bird behavior. Choice B involves multiple locations and times, which could introduce more variables and make it harder to analyze the data accurately. Choice D, counting birds at three feeders every 6 hours, may provide too frequent data points and not cover all significant time intervals for observing bird activity.

2. How is mitosis different from meiosis?

Correct answer: B

Rationale: Meiosis is the type of cell division that creates cells with half the number of chromosomes compared to the parent cell. This is essential for sexual reproduction as it ensures that when the sex cells (sperm and egg) combine during fertilization, the resulting offspring has the correct number of chromosomes. In contrast, mitosis results in two identical daughter cells with the same number of chromosomes as the parent cell. Choice A is incorrect because mitosis is responsible for the division of body cells, not sex cells. Choice C is incorrect because telophase is a phase that occurs in both mitosis and meiosis. Choice D is incorrect because spermatogenesis and oogenesis involve meiosis, not mitosis.

3. What is the first step in the conversion of glucose to pyruvate?

Correct answer: A

Rationale: The correct answer is Glycolysis. Glycolysis is the initial step in the conversion of glucose to pyruvate. During glycolysis, glucose is broken down into pyruvate through a series of enzymatic reactions. Choice B, the Krebs cycle, occurs after glycolysis in aerobic cellular respiration. Choice C, the Electron transport chain, is the final step in aerobic respiration where the majority of ATP is produced. Choice D, Aerobic respiration, is a broader term that encompasses glycolysis, the Krebs cycle, and the electron transport chain, but it is not the specific first step in the conversion of glucose to pyruvate.

4. What propels the cell forward?

Correct answer: B

Rationale: Propulsion, not microfilaments, cilia, or flagella, is what drives the cell forward. Propulsion is the force or process that propels the cell forward and allows it to move within its environment. Microfilaments are involved in cell structure, cilia are small hair-like structures for movement, and flagella are tail-like structures used for cell propulsion in some organisms.

5. What cycle is the sequence of reactions by which most living cells generate energy during aerobic respiration?

Correct answer: B

Rationale: The Krebs Cycle is the correct answer. It is a series of reactions occurring in the mitochondria and is a crucial part of aerobic respiration. The Calvin Cycle is a part of photosynthesis, not respiration, making choice A incorrect. Photosynthesis (choice C) is the process by which plants, algae, and some bacteria convert light energy into chemical energy. Fermentation (choice D) is an anaerobic process that does not require oxygen and is not the primary energy-generating pathway during aerobic respiration, so it is incorrect.

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