Nursing Elites

1. A restaurant employs servers, hosts, and managers in a ratio of 9:2:1. If there are 36 total employees, what is the number of hosts at the restaurant?

• A. 3
• B. 4
• C. 6
• D. 8

Correct answer: C

Rationale: To find the number of hosts in the restaurant, first, express the ratio algebraically as 9x + 2x + 1x = 36, where x represents the common factor. Combine like terms to get 12x = 36. Solve for x by dividing both sides by 12 to get x = 3. To find the number of hosts, multiply the coefficient of hosts (2) by x, which equals 6. Therefore, there are 6 hosts at the restaurant. Choice A, 3, is incorrect as it represents the number of servers. Choices B and D are incorrect as they do not correspond to the number of hosts based on the given ratio.

2. Solve the system of equations. Equation 1: 2x + y = 0 Equation 2: x - 2y = 8

• A. (1.8, 3.6) and (-1.8, -3.6)
• B. (1.8, -3.6) and (-1.8, 3.6)
• C. (1.3, 2.6) and (-1.3, -2.6)
• D. (-1.3, 2.6) and (1.3, -2.6)

Correct answer: B

Rationale: From Equation 1: 2x + y = 0. Solve for y: y = -2x. Substitute y = -2x into Equation 2: x - 2(-2x) = 8. Simplify to x + 4x = 8, then 5x = 8, and x = 8 ÷ 5 = 1.6. Substitute x = 1.6 back into y = -2x to find y = -3.2. Therefore, one solution is (1.6, -3.2). To find the second solution, use -1.6 for x to get (-1.6, 3.2). Thus, the correct answer is B, representing the solutions (1.8, -3.6) and (-1.8, 3.6). Choices A, C, and D contain incorrect values that do not match the solutions derived from solving the system of equations.

3. A mathematics test has a 4:2 ratio of data analysis problems to algebra problems. If the test has 18 algebra problems, how many data analysis problems are on the test?

• A. 24
• B. 28
• C. 36
• D. 38

Correct answer: C

Rationale: The ratio of 4:2 simplifies to 2:1. This means that for every 2 algebra problems, there is 1 data analysis problem. If there are 18 algebra problems, we can set up a proportion: 2 algebra problems correspond to 1 data analysis problem. Therefore, 18 algebra problems correspond to x data analysis problems. Solving the proportion, x = 18 * 1 / 2 = 9. Hence, there are 9 data analysis problems on the test. Therefore, the total number of data analysis problems on the test is 18 (algebra problems) + 9 (data analysis problems) = 27.

4. Round 8.067 to the nearest tenth.

• A. 8.1
• B. 8.1
• C. 8
• D. 8.11

Correct answer: A

Rationale: To round 8.067 to the nearest tenth, you look at the digit in the hundredth place, which is 6. Since 6 is equal to or greater than 5, you round up the digit in the tenth place. Therefore, 8.067 rounded to the nearest tenth is 8.1. Choice B (8.1) is incorrect as it duplicates the correct answer. Choice C (8) is incorrect as it does not account for the decimal part. Choice D (8.11) is incorrect as it rounds the number to the nearest hundredth, not the nearest tenth.

5. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

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