a gumball machine contains red orange yellow green and blue gumballs twenty percent of the gumballs are red 30 are orange 5 are yellow 10 are green an
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Nursing Elites

ATI TEAS 7

TEAS Practice Test Math

1. A gumball machine contains red, orange, yellow, green, and blue gumballs. Twenty percent of the gumballs are red, 30% are orange, 5% are yellow, 10% are green, and the rest are blue. If there are a total of 120 gumballs, how many more blue gumballs are there than yellow gumballs?

Correct answer: D

Rationale: The percentage of blue gumballs is 35% (100% - 20% - 30% - 5% - 10% = 35%). If there are 120 gumballs, 35% of that is 42 blue gumballs. Since 5% are yellow gumballs, which is 6 gumballs, the difference between 42 blue gumballs and 6 yellow gumballs is 36 more blue gumballs. Therefore, the correct answer is 36. Choice A (48) is incorrect as it miscalculates the difference. Choice B (30) is incorrect as it does not consider the correct percentage of blue gumballs. Choice C (42) is incorrect as it miscalculates the difference between blue and yellow gumballs.

2. Sally wants to buy a used truck for her delivery business. Truck A is priced at $450 and gets 25 miles per gallon. Truck B costs $650 and gets 35 miles per gallon. If gasoline costs $4 per gallon, how many miles must Sally drive to make truck B the better buy?

Correct answer: D

Rationale: To determine the breakeven point where Truck B becomes the better buy, we need to compare the total costs for both trucks. For Truck A: Total cost = $450 + (miles / 25) * $4. For Truck B: Total cost = $650 + (miles / 35) * $4. To find the point where Truck B is the better buy, set the two total cost equations equal to each other and solve for miles. By solving this equation, we find that Sally must drive 4375 miles for Truck B to be the better buy. Choice A (500) is too low, Choice B (7500) is too high, and Choice C (1750) does not represent the breakeven point where Truck B becomes more cost-effective.

3. In a graph that shows the number of nurses in various specialties, what is the independent variable?

Correct answer: C

Rationale: The independent variable is the variable that is controlled or manipulated in an experiment or study. In this case, the independent variable is the nurse specialties because it is the factor that is being observed and measured to see how it affects the number of nurses in each specialty. The dependent variable, which changes in response to the independent variable, is the number of nurses. Choices A and B are specific nurse specialties and are actually part of the data being measured, not the independent variable itself. Choice D, 'Number of nurses,' is the dependent variable as it is the outcome that is being influenced by the independent variable, which is the nurse specialties.

4. Alan currently weighs 200 pounds, but he wants to lose weight to get down to 175 pounds. What is the difference in kilograms? (1 pound is approximately equal to 0.45 kilograms.)

Correct answer: B

Rationale: The difference between Alan's current weight of 200 pounds and his goal weight of 175 pounds is 25 pounds (200 pounds - 175 pounds). To convert pounds to kilograms, you multiply the number of pounds by 0.45 (not divide by 2.2). Thus, 25 pounds is approximately 11.25 kilograms (25 pounds x 0.45). Therefore, the difference in kilograms is 11.25 kg. Choice A is incorrect because it miscalculates the conversion. Choices C and D are significantly higher values and do not reflect the correct conversion from pounds to kilograms.

5. Approximately how many people voted for the proposition if 9.5% of the town's population of 51,623 voted for it in a municipal election?

Correct answer: B

Rationale: To find the approximate number of people who voted for the proposition, multiply the town's population by the percentage that voted for it. 9.5% of 51,623 is about 0.095 * 51,623 ≈ 4,904. Rounded to the nearest thousand, this gives an estimate of 5,000 people. Therefore, choice B, '5,000,' is the correct answer. Choices A, C, and D are incorrect as they do not align with the calculated estimation.

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