a gift box has a length of 14 inches a height of 8 inches and a width of 6 inches how many square inches of wrapping paper are needed to wrap the box
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ATI TEAS 7

TEAS Practice Math Test

1. A gift box has a length of 14 inches, a height of 8 inches, and a width of 6 inches. How many square inches of wrapping paper are needed to wrap the box?

Correct answer: C

Rationale: To find the surface area of a rectangular prism, you use the formula SA = 2lw + 2wh + 2hl, where l is the length, w is the width, and h is the height. Substituting the given dimensions, the calculation would be SA = 2(14)(6) + 2(6)(8) + 2(8)(14) = 168 + 96 + 224 = 488 square inches. Therefore, 488 square inches of wrapping paper are needed to wrap the box. Choice A (56), Choice B (244), and Choice D (672) are incorrect because they do not represent the correct surface area calculation for the given box dimensions.

2. Apply the polynomial identity to rewrite (a + b)².

Correct answer: C

Rationale: When you see something like (a + b)², it means you're multiplying (a + b) by itself: (a + b)² = (a + b) × (a + b) To expand this, we use the distributive property (which says you multiply each term in the first bracket by each term in the second bracket): Multiply the first term in the first bracket (a) by both terms in the second bracket: a × a = a² a × b = ab Multiply the second term in the first bracket (b) by both terms in the second bracket: b × a = ab b × b = b² Now, add up all the results from the multiplication: a² + ab + ab + b² Since ab + ab is the same as 2ab, we can simplify it to: a² + 2ab + b² So, (a + b)² = a² + 2ab + b². This is known as a basic polynomial identity, and it shows that when you square a binomial (a two-term expression like a + b), you get three terms: the square of the first term (a²), twice the product of the two terms (2ab), and the square of the second term (b²). Therefore, the correct answer is C (a² + 2ab + b²)

3. Melissa is ordering fencing to enclose a square area of 5625 square feet. How many feet of fencing does she need?

Correct answer: C

Rationale: To find the side length of the square, we take the square root of the area: √5625 ft² = 75 ft. The perimeter of a square is 4 times its side length, so the fencing needed is 4 × 75 ft = 300 ft. Therefore, Melissa needs 300 feet of fencing to enclose the square area of 5625 square feet. Option A (75 feet) is the side length of the square, not the fencing needed. Option B (150 feet) is half of the correct answer and does not account for all sides of the square. Option D (5,625 feet) is the total area, not the length of fencing required.

4. One gallon of cleaning solution requires 6 oz of ammonia. If the maintenance department needs 230 gallons of solution to clean all of the floors, how much ammonia is needed?

Correct answer: C

Rationale: To find out how much ammonia is needed for 230 gallons of cleaning solution, you multiply the amount of ammonia needed per gallon by the total gallons of solution required. Therefore, 230 gallons * 6 oz/gallon = 1380 oz of ammonia. Option A ('1380 gallons') and Option B ('6900 gallons') are incorrect as the question asks for the amount of ammonia needed, not the total volume of cleaning solution. Option D ('1400 oz') is incorrect as it does not correctly calculate the amount of ammonia required based on the given information.

5. A soccer field is rectangular in shape and is 100 meters long and 75 meters wide. The hectare is a metric unit of area often used to measure larger areas. Given that 1 hectare = 10,000 square meters, which of the following represents the soccer field’s area in hectares?

Correct answer: A

Rationale: To find the area of the soccer field, multiply its length by its width: 100 meters × 75 meters = 7500 square meters. To convert this to hectares, divide by 10,000 (since 1 hectare = 10,000 square meters), resulting in 0.75 hectares. Therefore, the correct answer is A. Choices B, C, and D are incorrect because they do not correctly convert the area to hectares. B and C are off by a factor of 10, while D is off by a factor of 10,000.

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