Nursing Elites

1. Sarah works part-time and earns $12 per hour. If she works 20 hours a week, how much will she have saved in 5 weeks if she spends $50 per week on personal expenses?

• A. $600
• B. $750
• C. $500
• D. $650

Correct answer: C

Rationale: To find out how much Sarah saves in 5 weeks, first calculate her weekly earnings: $12/hour × 20 hours/week = $240/week. Then, subtract her weekly personal expenses from her earnings: $240/week - $50/week = $190/week saved. Over 5 weeks, she will save $190/week × 5 weeks = $950. However, none of the provided answer choices match $950. The closest option is $500, which is likely a mistake in the answer choices. The correct answer should have been $950 based on the calculated savings over 5 weeks.

2. A patient requires a 30% increase in the dosage of their medication. Their current dosage is 270 mg. What will their dosage be after the increase?

• A. 81 mg
• B. 270 mg
• C. 300 mg
• D. 351 mg

Correct answer: D

Rationale: To calculate a 30% increase from the current dosage of 270 mg, first find 30% of 270, which is 81 mg. Add this 81 mg increase to the original dosage of 270 mg to get the new dosage, which is 351 mg (270 mg + 81 mg = 351 mg). Therefore, the correct answer is 351 mg. Choice A (81 mg) is incorrect because this value represents only the calculated 30% increase, not the total dosage after the increase. Choice B (270 mg) is the original dosage and does not account for the 30% increase. Choice C (300 mg) is close to the correct answer but does not consider the precise 30% increase calculation, leading to an incorrect total dosage.

3. A cell has a diameter of 0.1 meter, and another cell has a diameter of 0.05 meters. How many times larger is the first cell compared to the second cell?

• A. 2
• B. 4
• C. 8
• D. 16

Correct answer: A

Rationale: To determine how many times larger the first cell is compared to the second cell, divide the diameter of the first cell by the diameter of the second cell: 0.1 / 0.05 = 2. Therefore, the first cell is 2 times larger than the second cell. Choice B, C, and D are incorrect because they do not provide the accurate calculation for the size difference between the two cells.

4. Two boxes are stacked, one measuring 4 inches tall and the other 6 inches tall. What is the total height of the stacked boxes?

• A. 10 inches
• B. 12 inches
• C. 8 inches
• D. 9 inches

Correct answer: A

Rationale: To find the total height of the stacked boxes, you need to add the height of each box together. Therefore, 4 inches (height of the first box) + 6 inches (height of the second box) = 10 inches, which is the total height of the stacked boxes. Choice B (12 inches) is incorrect because it adds the heights incorrectly. Choice C (8 inches) is incorrect as it does not consider both box heights. Choice D (9 inches) is incorrect as it also does not add the heights accurately.

5. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?

• A. Histogram
• B. Pie chart
• C. Bar graph
• D. Scatter plot

Correct answer: A

Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.

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