Nursing Elites

1. A commuter survey counts the people riding in cars on a highway in the morning. Each car contains only one man, only one woman, or both one man and one woman. Out of 25 cars, 13 contain a woman and 20 contain a man. How many contain both a man and a woman?

• A. 4
• B. 7
• C. 8
• D. 13

Correct answer: C

Rationale: Let's denote the number of cars containing only a man as M, only a woman as W, and both a man and a woman as B. Given that there are 25 cars in total, we have: M + W + B = 25 From the information provided, we know that 13 cars contain a woman (W) and 20 cars contain a man (M). Since each car contains either one man, one woman, or both, the cars that contain both a man and a woman (B) are counted once in each of the M and W categories. Therefore, to find out how many cars contain both a man and a woman, we need to subtract the number of cars that contain only a man and only a woman from the total cars. M + B = 20 (as 20 cars contain a man) W + B = 13 (as 13 cars contain a woman) Solving the above two equations simultaneously, we get: M = 12, W = 5, B = 8 Therefore, 8 cars contain both a man and a woman. Hence, the correct answer is 8. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on the information provided.

2. Which percentage is greatest?

• A. The percentage of Asian Americans among the staff at Hospital X
• B. The percentage of staff members who have been on staff for 10-15 years at Hospital X
• C. The percentage of Doctors among the staff at Hospital X and Hospital Y
• D. The percentage of staff with 1-4 complaints among the staff at Hospital Y

Correct answer: C

Rationale: To determine the highest percentage, we need to calculate each option. The percentage in answer A is: 50 / 250 x 100 = 20%. The percentage in answer B is: 57 / 250 x 100 = 22.8%. The percentage in answer C is: (74 + 55) / 433 x 100 = 29.8%. The percentage in answer D is: 21 / 183 x 100 = 11.5%. Therefore, the correct answer is C, as it has the highest percentage of doctors among the staff at both hospitals. Choices A, B, and D are incorrect as they have lower percentages compared to choice C.

3. A farmer plans to install fencing around a certain field. If each side of the hexagonal field is 320 feet long, and fencing costs $75 per foot, how much will the farmer need to spend on fencing material to enclose the perimeter of the field?

• A. $2,240
• B. $2,800
• C. $3,360
• D. $4,480

Correct answer: C

Rationale: The field is a hexagon with six equal sides, each 320 feet long. To find the total cost of fencing material needed, multiply the cost per foot ($75) by the total perimeter of the field (6 sides x 320 feet). Therefore, the total cost will be $75 x 6 x 320 = $3,360. Thus, the farmer will need to spend $3,360 on fencing material. Choice A, $2,240, is incorrect as it does not account for the total perimeter of the field. Choice B, $2,800, is incorrect as it underestimates the total cost by not considering all sides of the hexagon. Choice D, $4,480, is incorrect as it overestimates the total cost by multiplying incorrectly or considering extra sides.

4. A patient was taking 310 mg of an antidepressant daily. The doctor reduced the dosage by 1/5, and then reduced it again by 20 mg. What is the patient’s final dosage?

• A. 20 mg
• B. 42 mg
• C. 228 mg
• D. 248 mg

Correct answer: C

Rationale: To calculate the final dosage, first find 1/5 of 310 mg, which is 62 mg, and subtract it from the original dosage. This gives 310 mg - 62 mg = 248 mg. Then, subtract an additional 20 mg from the result to get the final dosage: 248 mg - 20 mg = 228 mg. Therefore, the patient's final dosage is 228 mg. Choice A (20 mg) is incorrect because it only considers the second reduction of 20 mg and misses the initial reduction by 1/5. Choice B (42 mg) is incorrect as it miscalculates the reduction amounts. Choice D (248 mg) is incorrect as it does not account for the second reduction of 20 mg.

5. A study about anorexia was conducted on 100 patients. 70% were women, and 10% of the men were overweight as children. How many male patients were not overweight as children?

• A. 3
• B. 10
• C. 27
• D. 30

Correct answer: C

Rationale: Out of the 100 patients, 30% were men, which equals 30 male patients. It is given that 10% of the men were overweight as children, so 10% of 30 is 3, meaning 3 male patients were overweight. Therefore, the remaining 27 male patients were not overweight as children. Choice A, B, and D are incorrect as they do not accurately represent the number of male patients who were not overweight.

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