HESI A2
HESI A2 Physics
1. A closed system undergoes a cyclic process, returning to its initial state. What can be said about the net work done (Wnet) by the system over the entire cycle?
- A. Wnet is always positive.
- B. Wnet is always negative.
- C. Wnet can be positive, negative, or zero.
- D. Wnet is equal to the total heat transferred into the system (dQ ≠0 for a cycle).
Correct answer: C
Rationale: For a closed system undergoing a cyclic process and returning to its initial state, the net work done (Wnet) over the entire cycle can be positive, negative, or zero. This is because the work done is determined by the area enclosed by the cycle on a P-V diagram, and this area can be above, below, or intersecting the zero work axis, leading to positive, negative, or zero net work done. Choice A is incorrect because Wnet is not always positive; it depends on the specific path taken on the P-V diagram. Choice B is incorrect as Wnet is not always negative; it varies based on the enclosed area. Choice D is incorrect because Wnet is not necessarily equal to the total heat transferred into the system; it depends on the specifics of the cycle and is not a direct relationship.
2. When a charged particle moves through a vacuum at a constant speed, it generates:
- A. An electric field only
- B. A magnetic field only
- C. Both an electric and magnetic field
- D. Neither an electric nor magnetic field
Correct answer: C
Rationale: A moving charged particle generates both an electric field and a magnetic field. The electric field is due to the charge itself, and the magnetic field is produced by the motion of the charge. Choice A is incorrect because a moving charged particle also generates a magnetic field. Choice B is incorrect because a moving charged particle generates both electric and magnetic fields. Choice D is incorrect as a moving charged particle generates fields due to its charge and motion.
3. In open-channel flow, a critical property is the free surface, which refers to the:
- A. Interface between the liquid and the container walls
- B. Interface between the liquid and a surrounding gas
- C. Bottom of the channel
- D. Region of highest velocity within the liquid
Correct answer: B
Rationale: The free surface in open-channel flow refers to the interface between the liquid and the surrounding gas, typically the atmosphere. This interface is critical as it determines the boundary between the liquid flow and the open environment. Option A is incorrect as it refers to the liquid-container wall interface, not the free surface. Option C is incorrect because it represents the bottom of the channel, not the free surface. Option D is incorrect as it describes the region of highest velocity within the liquid, not the free surface. Therefore, the correct choice is B.
4. Jack stands in front of a plane mirror. If he is 5 feet away from the mirror, how far away from Jack is his image?
- A. 2.5 feet
- B. 3 feet
- C. 4.5 feet
- D. 5 feet
Correct answer: D
Rationale: When Jack stands in front of a plane mirror, his image appears the same distance behind the mirror as Jack is in front of it. Therefore, if Jack is 5 feet away from the mirror, his image will also appear 5 feet behind the mirror. The total distance from Jack to his image is the sum of these distances, which equals 10 feet. Choices A, B, and C are incorrect because the image distance is not half of the total distance but the same as the object's distance from the mirror.
5. A wave in a rope travels at 12 m/s and has a wavelength of 2 m. What is the frequency?
- A. 38.4 Hz
- B. 6 Hz
- C. 4.6 Hz
- D. 3.75 Hz
Correct answer: B
Rationale: The frequency of a wave is calculated using the formula: frequency = speed / wavelength. In this case, the speed of the wave is 12 m/s and the wavelength is 2 m. Therefore, the frequency is calculated as 12 m/s / 2 m = 6 Hz. Choice A (38.4 Hz), Choice C (4.6 Hz), and Choice D (3.75 Hz) are incorrect as they do not result from the correct calculation using the given values.
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