while at the local ice skating rink cora went around the rink 27 times total she slipped and fell 20 of the 27 times she skated around the rink what a
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ATI TEAS 7

TEAS Practice Math Test

1. While at the local ice skating rink, Cora went around the rink 27 times in total. She slipped and fell 20 of the 27 times she skated around the rink. What approximate percentage of the times around the rink did Cora not slip and fall?

Correct answer: C

Rationale: To find the approximate percentage of the times Cora did not slip and fall, subtract the times she fell (20) from the total times around the rink (27), which gives 7. Then, divide the number of times she did not slip and fall (7) by the total times around the rink (27) and multiply by 100 to get the percentage. So, 7 divided by 27 equals 0.259, which rounds to approximately 26%. Therefore, the correct answer is 26%. Choice A (37%) is incorrect because it does not reflect the calculation based on the given information. Choice B (74%) is incorrect as it is not the result of the correct calculation. Choice D (15%) is incorrect as it does not match the calculated percentage based on the scenario provided.

2. What score must Dwayne get on his next math test to maintain an overall average of at least 90?

Correct answer: B

Rationale: To maintain an overall average of at least 90, Dwayne must aim for a score of 90 on every test. If his current average is below 90, he needs to make up for it by scoring higher on upcoming tests. Choosing 98 ensures that his overall average remains at or above 90. Choice A (89) is below the desired average of 90, so it would not be sufficient. Choices C (95) and D (100) are higher than necessary to maintain an average of at least 90.

3. Margery is planning a vacation, and her round-trip airfare will cost $572. Her hotel costs $89 per night, and she will be staying at the hotel for five nights. She has allotted a total of $150 for sightseeing and expects to spend about $250 on meals. She will receive a 10% discount on the hotel price after the first night. What is the total amount Margery expects to spend on her vacation?

Correct answer: C

Rationale: To calculate Margery's total expenses: Airfare ($572) + Hotel ($89 * 5 nights) = $572 + $445 = $1017. After the first night's stay, Margery receives a 10% discount on the remaining four nights, making the total hotel cost $445 - (10% of $89) = $445 - $8.90 = $436.10. Adding sightseeing ($150) and meals ($250) to the total gives $1017 + $150 + $250 = $1417. Margery's expected expenses are $1417, not $1381.40 as stated in the original rationale. Therefore, the correct answer is $1,417.60 (Option D).

4. Solve the following equation: 3(2y+50)βˆ’4y=500

Correct answer: B

Rationale: To solve the equation 3(2y+50)βˆ’4y=500, first distribute to get 6y+150βˆ’4y=500. Combining like terms results in 2𝑦 + 150 = 500. By subtracting 150 from both sides, we get 2y = 350. Dividing by 2 gives y = 175. Therefore, the correct answer is B. Choices A, C, and D are incorrect because they do not correctly follow the steps of distributing, combining like terms, and isolating the variable to solve for y.

5. What is the probability of consecutively pulling two more orange blocks, without replacement, from a bag containing 3 orange blocks, 5 green blocks, and 4 purple blocks?

Correct answer: B

Rationale: To calculate the probability of consecutively pulling two more orange blocks without replacement, we first determine the probability of pulling an orange block on the first draw, which is 3/12 (3 orange blocks out of 12 total blocks). After removing one orange block, there are only 11 blocks left, so the probability of pulling another orange block on the second draw is 2/11. To find the combined probability, we multiply the probabilities together: (3/12) * (2/11) = 6/132 = 3/55. Therefore, the correct answer is B. Choice A (3/12) incorrectly simplifies the probability before calculating the second draw. Choice C (2/10) does not consider the specific number of orange blocks in the bag. Choice D (1/3) does not account for the reduced number of blocks after the first draw.

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