ATI TEAS 7
Practice TEAS Science Test
1. Which of the following structures prevents food from entering the windpipe?
- A. Pharynx
- B. Esophagus
- C. Larynx
- D. Epiglottis
Correct answer: D
Rationale: The epiglottis is the structure that prevents food from entering the windpipe by covering the trachea during swallowing. When food is swallowed, the epiglottis folds over the opening of the trachea to ensure that food goes down the esophagus and not into the airway. The pharynx is a shared pathway for both food and air, leading to the esophagus and larynx respectively. The esophagus is the muscular tube that carries food from the throat to the stomach. The larynx is responsible for producing sound and protecting the airway during swallowing, but the epiglottis is specifically designed to prevent food from entering the windpipe.
2. Which organ produces insulin and glucagon?
- A. Salivary Glands
- B. Liver
- C. Gallbladder
- D. Pancreas
Correct answer: D
Rationale: The correct answer is D, Pancreas. The pancreas is the organ responsible for producing the hormones insulin and glucagon. Insulin functions to lower blood sugar levels by facilitating the uptake of glucose by cells for energy production. On the other hand, glucagon works to raise blood sugar levels by prompting the liver to release stored glucose into the bloodstream. The pancreas is a vital organ in the endocrine system, playing a crucial role in maintaining appropriate blood sugar levels in the body. Choices A, B, and C are incorrect as the salivary glands produce saliva, the liver is involved in various metabolic functions, and the gallbladder stores bile produced by the liver, but none of these organs produce insulin and glucagon.
3. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?
- A. 31.25 mL
- B. 32 mL
- C. 30 mL
- D. 31.3 mL
Correct answer: B
Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.
4. What is the main component of stomach acid?
- A. Hydrochloric acid
- B. Bicarbonate
- C. Bile salts
- D. Enzymes
Correct answer: A
Rationale: Stomach acid, also known as gastric acid, is primarily composed of hydrochloric acid. Hydrochloric acid plays a crucial role in the digestive process by helping to break down food and kill bacteria in the stomach. Bicarbonate is a base that helps neutralize stomach acid in the small intestine, but it is not the main component of stomach acid. Bile salts are produced by the liver and stored in the gallbladder, aiding in the digestion and absorption of fats, but they are not the main component of stomach acid. Enzymes are proteins that help catalyze chemical reactions in the body, including the breakdown of food molecules during digestion, but they are not the main component of stomach acid.
5. How many moles of water are produced when 0.5 moles of methane (CH4) react with excess oxygen?
- A. 0.5 moles
- B. 1 mole
- C. 2 moles
- D. 3 moles
Correct answer: B
Rationale: The balanced chemical equation for the combustion of methane is: CH4 + 2O2 -> CO2 + 2H2O. This equation shows that 1 mole of methane produces 2 moles of water. Therefore, when 0.5 moles of methane react, they will produce 1 mole of water. The ratio of water to methane is 2:1, meaning that for every mole of methane that reacts, it produces 2 moles of water. Since only 0.5 moles of methane are reacting, the amount of water produced will be half of what would be produced if 1 mole of methane reacted, resulting in 1 mole of water being produced. Choice A is incorrect because it does not consider the stoichiometry of the reaction. Choices C and D are incorrect as they do not align with the balanced chemical equation and the stoichiometric ratios involved in the reaction.
Similar Questions
Access More Features
ATI TEAS Premium Plus
$149.99/ 90 days
- Actual ATI TEAS 7 Questions
- 3,000 questions with answers
- 90 days access
ATI TEAS Basic
$1/ 30 days
- 3,000 Questions with answers
- 30 days access