Nursing Elites

1. Which of the following statements regarding the pericardium is not correct?

• A. It allows for the heart to work in a relatively friction-free environment
• B. It is a single-walled layer around the heart
• C. It prevents overfilling of the heart with blood
• D. It protects and anchors the heart

Correct answer: B

Rationale: The correct statement about the pericardium is that it is double-walled, not single-walled. Choice A is correct because the pericardium does allow the heart to work in a relatively friction-free environment, reducing friction during heartbeats. Choice C is correct as the pericardium helps prevent the overfilling of the heart with blood. Choice D is also correct as the pericardium serves to protect and anchor the heart in place within the chest cavity.

2. Which of the following is a genetic condition that affects the respiratory system?

• A. Asthma
• B. Cystic fibrosis
• C. Mycosis
• D. Surfactant Deficiency

Correct answer: B

Rationale: The correct answer is B, Cystic fibrosis. Cystic fibrosis is a genetic disorder that primarily affects the respiratory and digestive systems. It leads to the production of thick mucus in the lungs, causing breathing difficulties and increasing the risk of respiratory infections. Choice A, Asthma, is a chronic respiratory condition characterized by inflammation and narrowing of the airways, but it is not a genetic condition. Choice C, Mycosis, refers to fungal infections and is not a genetic condition specifically affecting the respiratory system. Choice D, Surfactant Deficiency, is a condition related to respiratory distress syndrome in newborns and is not a genetic disorder affecting the respiratory system in general.

3. Which literary device is most prominent in Wilde's play?

• A. Irony
• B. Symbolism
• C. Metaphor
• D. Allusion

Correct answer: A

Rationale: The correct answer is 'Irony.' Irony is the most prominent literary device in Wilde's play, 'The Importance of Being Earnest,' as it pervades his critique of the upper class. Throughout the play, Wilde uses irony to highlight the absurdities and trivialities of the British aristocracy. The characters engage in witty and humorous dialogue filled with situational irony, verbal irony, and dramatic irony, exposing the superficiality and hypocrisy of the upper classes. Symbolism, metaphor, and allusion are present in the play but to a lesser extent compared to irony. While symbolism and metaphor are used to enhance the themes and characterizations, allusion is sparingly employed. However, it is the pervasive use of irony that sets the tone and drives Wilde's satire of the societal norms and values of the time.

4. Simplify the following expression: (1/4) × (3/5) ÷ 1 (1/8)

• A. 8/15
• B. 27/160
• C. 2/15
• D. 27/40

Correct answer: C

Rationale: First, convert the mixed number 1 (1/8) into an improper fraction: 1 (1/8) = 9/8. Now, simplify the expression: (1/4) × (3/5) ÷ (9/8). To divide by a fraction, multiply by its reciprocal: (1/4) × (3/5) × (8/9) = 24/180 = 2/15. Thus, the simplified expression is 2/15. Choice A (8/15) is incorrect because the correct answer is 2/15. Choice B (27/160) is incorrect as it is not the result of the given expression. Choice D (27/40) is incorrect as it does not match the simplified expression obtained.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

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