ATI TEAS 7
ATI TEAS Science Test
1. Which nervous system controls voluntary motor movement?
- A. Parasympathetic
- B. Sympathetic
- C. Autonomic
- D. Somatic
Correct answer: D
Rationale: The correct answer is D: Somatic. The somatic nervous system is responsible for controlling voluntary motor movements. It includes the motor neurons that innervate skeletal muscles and allows us to consciously control our movements. The parasympathetic and sympathetic nervous systems are part of the autonomic nervous system, which controls involuntary functions such as heart rate and digestion. Therefore, choices A, B, and C are incorrect as they are components of the autonomic nervous system and are not primarily responsible for voluntary motor movements.
2. Nuclear fusion powers the sun and other stars. What is the main obstacle to achieving controlled nuclear fusion on Earth for energy production?
- A. Lack of suitable materials to handle high temperatures and pressures.
- B. Limited availability of fusion fuels like deuterium and tritium.
- C. Difficulty in containing the plasma where fusion occurs.
- D. All of the above
Correct answer: D
Rationale: The main obstacle to achieving controlled nuclear fusion on Earth for energy production involves a combination of factors. A) Lack of suitable materials to handle high temperatures and pressures is a significant challenge due to the extreme conditions required for fusion reactions. B) Limited availability of fusion fuels like deuterium and tritium can pose a constraint on the scalability and sustainability of fusion energy. C) Difficulty in containing the plasma where fusion occurs is another critical issue as plasma instabilities and heat losses can hinder the efficiency of fusion reactions. Therefore, all of the options (A, B, and C) contribute to the challenges in achieving controlled nuclear fusion for energy production on Earth.
3. What is the tough, fibrous connective tissue that attaches muscle to bone?
- A. Fascia
- B. Perimysium
- C. Tendon
- D. Ligament
Correct answer: C
Rationale: Tendons are the correct answer as they are the tough, fibrous connective tissues that attach muscle to bone. They play a crucial role in transmitting the forces generated by muscle contraction to the bones, facilitating movement. Fascia surrounds muscles and provides support, perimysium is the connective tissue sheath around muscle fibers, and ligaments connect bone to bone, stabilizing joints, which makes them distinct from tendons.
4. Which of the following is the main organ responsible for producing bile?
- A. Liver
- B. Gallbladder
- C. Pancreas
- D. Stomach
Correct answer: A
Rationale: The liver is the main organ responsible for producing bile. Bile, a greenish-yellow fluid, is produced by the liver and stored in the gallbladder. Its primary function is to aid in the digestion and absorption of fats in the small intestine. When needed, the gallbladder releases bile into the small intestine to facilitate fat digestion. The pancreas produces digestive enzymes and insulin, not bile, making choice C incorrect. The stomach's primary role is to digest food through gastric juice secretion, making choice D incorrect. Therefore, the correct answer is the liver, as it is the main organ responsible for bile production.
5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.
- A. 18.3 g
- B. 19.7 g
- C. 21.0 g
- D. 24.2 g
Correct answer: B
Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.
Similar Questions
Access More Features
ATI TEAS Premium Plus
$150/ 90 days
- Actual ATI TEAS 7 Questions
- 3,000 questions with answers
- 90 days access
ATI TEAS Basic
$99/ 30 days
- 3,000 Questions with answers
- 30 days access