ATI TEAS 7
TEAS 7 science practice questions
1. When calcium chloride (CaCl2) dissolves in water, it separates into its ions (Ca2+ and Cl-). This is an example of:
- A. Chemical change
- B. Physical change
- C. Precipitation
- D. Neutralization
Correct answer: B
Rationale: When calcium chloride dissolves in water, it separates into its ions without forming a new substance, which is characteristic of a physical change. A physical change involves alterations in the substance's physical properties without changing its chemical composition. In this scenario, the chemical formula of calcium chloride remains unchanged, and only its physical state changes by creating ions in the solution. Therefore, the dissolution of calcium chloride in water is an example of a physical change. Choice A, 'Chemical change,' is incorrect because no new substances are formed during the dissolution process. Choice C, 'Precipitation,' is incorrect as precipitation involves the formation of an insoluble solid when two solutions react. Choice D, 'Neutralization,' is incorrect as it refers to a reaction between an acid and a base to form salt and water, which is not the case in the given scenario.
2. What is the significance of the nuclear envelope breaking down during mitosis?
- A. It allows the chromosomes to condense and become visible.
- B. It allows the spindle apparatus to form and attach to the chromosomes.
- C. It allows the sister chromatids to separate.
- D. It allows the nuclear material to be evenly distributed to the daughter cells.
Correct answer: B
Rationale: A) The breakdown of the nuclear envelope does not directly cause the chromosomes to condense and become visible. Chromosome condensation is a separate process that occurs before mitosis begins. B) The breakdown of the nuclear envelope is crucial for the formation of the spindle apparatus, a structure made of microtubules that helps separate the chromosomes during cell division. The spindle apparatus attaches to the chromosomes and helps move them to opposite poles of the cell. C) The separation of sister chromatids occurs during anaphase, which is facilitated by the spindle apparatus. The breakdown of the nuclear envelope is not directly involved in this process. D) The even distribution of nuclear material to daughter cells is achieved through the movement of chromosomes by the spindle apparatus, which is made possible by the breakdown of the nuclear envelope.
3. Which of the following is NOT a type of asexual reproduction in bacteria?
- A. Binary fission
- B. Conjugation
- C. Budding
- D. Transduction
Correct answer: D
Rationale: A) Binary fission: This is a common method of asexual reproduction in bacteria where a single cell divides into two identical daughter cells. B) Conjugation: This is a process in which genetic material is transferred between bacterial cells through direct cell-to-cell contact, leading to genetic recombination. C) Budding: Budding is a form of asexual reproduction where a new organism develops from an outgrowth or bud on the parent organism. D) Transduction: Transduction is a method of horizontal gene transfer in bacteria where genetic material is transferred from one bacterium to another by a bacteriophage (a virus that infects bacteria). It is not a form of asexual reproduction in bacteria. Therefore, the correct answer is D) Transduction, as it is not a type of asexual reproduction in bacteria but a mechanism of genetic exchange.
4. Which of the following is NOT a state of matter?
- A. Solid
- B. Liquid
- C. Gas
- D. Superfluid
Correct answer: D
Rationale: The correct answer is 'Superfluid.' Superfluid is not considered a traditional state of matter. It is a unique phase of matter that displays zero viscosity and flows without losing kinetic energy. Solids, liquids, and gases are the three classical states of matter distinguished by their physical properties and structures. Therefore, choices A, B, and C are considered states of matter, while choice D, superfluid, is not.
5. Which vitamin is produced when the skin is exposed to sunlight?
- A. Vitamin A
- B. Vitamin D
- C. Vitamin K
- D. Vitamin E
Correct answer: B
Rationale: Vitamin D is the correct answer. When the skin is exposed to sunlight, it triggers a process where a form of cholesterol in the skin is converted into vitamin D. This vitamin plays a crucial role in aiding calcium absorption in the gut, which is essential for maintaining strong and healthy bones. Vitamin A (Choice A) is important for vision and immune function but is not produced by sunlight exposure. Vitamin K (Choice C) is known for its role in blood clotting and bone metabolism, but it is not produced by sunlight. Vitamin E (Choice D) is an antioxidant that protects cells from damage but is not synthesized in the skin through sunlight exposure.
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