ATI TEAS 7
TEAS 7 science practice
1. What is the work done by a force of 20 N acting on an object that moves 5 meters in the direction of the force?
- A. 100 Joules (J)
- B. 25 Joules (J)
- C. 4 Joules (J)
- D. Work cannot be determined without knowing the object's mass.
Correct answer: A
Rationale: The work done is calculated using the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. In this case, the force and the direction of motion are in the same direction, so cos(theta) = 1. Therefore, Work = 20 N x 5 m x 1 = 100 Joules. Since the force and distance are given and are in the same direction, the work done can be directly calculated without needing to know the object's mass. Choice A, 100 Joules, is the correct answer as calculated. Choice B and C are incorrect as they do not correspond to the correct calculation. Choice D is incorrect because knowing the object's mass is not necessary to calculate work in this scenario, as work is dependent on force, distance, and the angle between them, not mass.
2. In which position allows access to the stomach?
- A. Medial
- B. Prone
- C. Superficial
- D. Supine
Correct answer: B
Rationale: The question now specifies the need for a position that allows access to the stomach. The correct answer is 'B: Prone.' In the prone position, the patient lies face down, which facilitates access to the stomach for various procedures or examinations. Choice A, 'Medial,' refers to a direction rather than a patient position. Choice C, 'Superficial,' describes a superficial depth rather than a patient position. Choice D, 'Supine,' is a position where the patient lies face up, which does not provide easy access to the stomach.
3. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?
- A. 31.25 mL
- B. 32 mL
- C. 30 mL
- D. 31.3 mL
Correct answer: B
Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.
4. Which statement below best describes the process of condensation?
- A. Condensation is the process of changing from a gas to a liquid.
- B. Condensation is the process of changing from a liquid to a gas.
- C. Condensation is the process of changing from a solid to a liquid.
- D. Condensation is the process of changing from a solid to a gas.
Correct answer: A
Rationale: The correct answer is A: 'Condensation is the process of changing from a gas to a liquid.' Condensation occurs when a gas cools and transforms into a liquid state. For example, when water vapor in the air cools and forms droplets, it is an example of condensation. This process is commonly observed in the formation of clouds or dew on grass in the early morning. Choice B is incorrect because it describes the process of vaporization rather than condensation. Choice C is incorrect as it refers to the process of melting. Choice D is incorrect as it describes sublimation, which is the transition from a solid to a gas without passing through the liquid phase.
5. Which of the following substances can donate a hydroxide ion (OH-) in solution?
- A. Salt
- B. Base
- C. Neutral compound
- D. Dehydrating agent
Correct answer: B
Rationale: The correct answer is B: Base. A base is a substance that can donate hydroxide ions (OH-) in solution. Bases increase the concentration of hydroxide ions by either accepting protons (H+) or donating hydroxide ions. Salts are ionic compounds made of cations and anions, which do not directly donate hydroxide ions. Neutral compounds do not significantly affect the concentration of hydroxide ions. Dehydrating agents are substances that remove water molecules from other compounds, unrelated to donating hydroxide ions.
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